LightFM如何预测新用户(冷启动)-用户id 8不在用户id映射中



我正在构建一个推荐系统,以便根据用户特性和项目特性向员工推荐培训,LightFM根据文档,这是一个很好的算法。

我的用户数据帧:

User-Id name    age los ou  gender  skills
0   1   Luis    21  IFS architecture    M   python
1   2   Peter   22  ADV pmo M   pm
2   3   Jurgen  23  IFS architecture    M   sql
3   4   Bart    24  IFS architecture    M   python
4   5   Cristina    25  ADV pmo F   pm
5   6   Lambert 33  IFS development M   sql
6   7   Rahul   44  IFS development M   python

我的训练数据帧

Training-Id training name   main skill
0   1   basic python    python
1   2   advanced python python
2   3   basic scrum pm
3   4   advanced scrum  pm
4   5   basic sql   sql
5   6   advanced sql    sql

我的培训采用了数据帧(10表示用户接受了该培训(所以我的重量只有10

User-Id Training-Id TrainingTaken
0   1   1   10
1   1   2   10
2   2   3   10
3   2   4   10
4   3   5   10
5   3   6   10
6   4   1   10
7   4   2   10

为了创建tha矩阵,我发现了一个很好的帮助工具:https://github.com/Med-ELOMARI/LightFM-Dataset-Helper

因此:

items_column = "Training-Id"
user_column = "User-Id"
ratings_column = "TrainingTaken"
items_feature_columns = [
"training name",
"main skill"
]
user_features_columns = ["name","age","los","ou", "gender", "skills"]
dataset_helper_instance = DatasetHelper(
users_dataframe=usersdf,
items_dataframe=trainingsdf,
interactions_dataframe=trainingstakendf,
item_id_column=items_column,
items_feature_columns=items_feature_columns,
user_id_column=user_column,
user_features_columns=user_features_columns,
interaction_column=ratings_column,
clean_unknown_interactions=True,
)
# run the routine
# you can alslo run the steps separately one by one | routine function is simplifying the flow
dataset_helper_instance.routine()

上述助手返回交互矩阵、权重矩阵等

dataset_helper_instance.weights.todense()
Output menu
matrix([[10., 10.,  0.,  0.,  0.,  0.],
[ 0.,  0., 10., 10.,  0.,  0.],
[ 0.,  0.,  0.,  0., 10., 10.],
[10., 10.,  0.,  0.,  0.,  0.],
[ 0.,  0.,  0.,  0.,  0.,  0.],
[ 0.,  0.,  0.,  0.,  0.,  0.],
[ 0.,  0.,  0.,  0.,  0.,  0.]], dtype=float32)

dataset_helper_instance.interactions.todense()
matrix([[1., 1., 0., 0., 0., 0.],
[0., 0., 1., 1., 0., 0.],
[0., 0., 0., 0., 1., 1.],
[1., 1., 0., 0., 0., 0.],
[0., 0., 0., 0., 0., 0.],
[0., 0., 0., 0., 0., 0.],
[0., 0., 0., 0., 0., 0.]], dtype=float32)

然后我训练测试拆分并拟合模型

from lightfm import LightFM
from lightfm.cross_validation import random_train_test_split
(train, test) = random_train_test_split(interactions=dataset_helper_instance.interactions, test_percentage=0.2)
model = LightFM(loss='warp')
model.fit(
interactions=dataset_helper_instance.interactions,
sample_weight=dataset_helper_instance.weights,
item_features=dataset_helper_instance.item_features_list,
user_features=dataset_helper_instance.user_features_list,
verbose=True,
epochs=50,
num_threads=20,
)

然后我检查AUC和精度:

from lightfm.evaluation import precision_at_k
from lightfm.evaluation import auc_score
train_precision = precision_at_k(model, train,item_features=dataset_helper_instance.item_features_list, user_features=dataset_helper_instance.user_features_list , k=10).mean()
test_precision = precision_at_k(model, test, item_features=dataset_helper_instance.item_features_list, user_features=dataset_helper_instance.user_features_list,k=10).mean()
train_auc = auc_score(model, train,item_features=dataset_helper_instance.item_features_list, user_features=dataset_helper_instance.user_features_list).mean()
test_auc = auc_score(model, test,item_features=dataset_helper_instance.item_features_list, user_features=dataset_helper_instance.user_features_list).mean()
print('Precision: train %.2f, test %.2f. '% (train_precision, test_precision))
print('AUC: train %.2f, test %.2f.' % (train_auc, test_auc))
Precision: train 0.15, test 0.10. 
AUC: train 0.90, test 1.00.

然后我为现有用户做预测

scores = model.predict(user_ids=6, item_ids=[1,2,3,5,6])
print(scores)
[ 0.01860116 -0.20987387  0.06134995  0.08332028  0.13678455]

太好了,我可以得到一些关于用户ID 6的训练预测。

现在我想预测新用户,(冷启动(

我尝试了以下方法:

dataset = Dataset()
new_user_feature = [8,{'name:John', 'Age:33', 'los:IFS','ou:development', 'skills:sql'} ]    
new_user_feature = [8,new_user_feature]
new_user_feature = dataset.build_user_features([new_user_feature])
#predict new users User-Id  name    age los ou  gender  skills
model.predict(0, item_ids=[1,2,3,5,6], user_features=new_user_feature)

然而,我得到了这个错误:

ValueError: user id 8 not in user id mappings.

我在这里错过了什么?

我无法测试它,但我认为问题出在您编写时

new_user_feature = [8,{'name:John', 'Age:33', 'los:IFS','ou:development', 'skills:sql'} ]    
new_user_feature = [8,new_user_feature]

根据文档,dataset.build_user_features(..)想要形式为(user id, [list of feature names])(user id, {feature name: feature weight})的可迭代项。

在您的情况下,我认为您应该将上面的两行替换为:

new_user_feature = [8,{'name':'John', 'Age':33, 'los':'IFS','ou':'development', 'skills':'sql'} ]
# Is the gender missing?    

如果它不起作用,也许输入格式是这样的:

new_user_feature = [8,['John', 33, 'IFS', 'development', 'sql'] ]    

让我知道它是否解决了问题

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