使用bs4，我找到了一种获取网页标题和描述的方法，但描述是用省略号分割的，就像这个"Everything you need to know about how-to adopt a cat, bringing your new cat... Browse cat breeds and learn about the many cats available for adoption on..."
这是我的代码：
def get_data(search):
headers = {"user-agent" : get_headers()} # get_headers is just the value of a file with viewing headers
response = requests.get("https://www.google.com/search", params={"q" : search}, headers = headers)
results = page_info(response.content)
return results
def page_info(page):
soup = BeautifulSoup(page, "lxml")
names = soup.find_all("h3", class_ = "LC20lb DKV0Md")
links = soup.find_all("cite", class_ = "iUh30 Zu0yb qLRx3b tjvcx")
desc = soup.find_all("div", class_ = "VwiC3b yXK7lf MUxGbd yDYNvb lyLwlc")
parsed_data = [{"title":title.text, "link":link.text.replace(" › ","/"), "desc":desc.text} for title, link, desc in zip(names, links, desc)]
return parsed_data
有没有办法在没有...的情况下获得描述？谢谢编辑：为了更清楚，我的意思是得到完整的描述，或者至少比提供的描述更完整。
您可以拆分该字符串，然后从中生成一个新字符串
disc = "Everything you need to know about how-to adopt a cat, bringing your new cat... Browse cat breeds and learn about the many cats available for adoption on..."
#this splits the description by '...' and returns array
splited = disc.split('...')
#now join the elements in array and make another string out of it
final = ''.join(splited)
# you can change this line to final = ' '.join(splited) and add space between those splited strings
您可以使用String.replace()删除(或替换(字符串的任何部分
示例：
original_str = "abc ... 123... abc"
corrected_str = original_str.replace('...', '')
print(original_str)
print(corrected_str)
输出：
abc ... 123... abc
abc 123 abc