附加具有相同键的另一个字典中的字典值

Question

我有以下两个字典：

flow = {(49, 53): [122.92], (105, 34): [40.26], (47, 92): [85.28], ...} --- len(flow) = 134
dist= {(101, 15): 688, (47, 92): 156, (13, 62): 208, ...} --- len(dist) = 172

flow的所有密钥都包含在dist中(flow密钥是dist密钥的子集(，我基本上想把dist中的所有距离附加到flow的值上，得到如下：

flow_dist = {(49, 53): [122.92, 151], (105, 34): [40.26, 203], (47, 92): [85.28, 156], ...}

到目前为止我所拥有的：

list = [flow, dist]
new_dict = {key: [elem.get(key) for elem in list] for key in set().union(*list)}

输出：flow_dist = {(49, 53): [[122.92], 151], (105, 34): [[40.26], 203], (47, 92): [[85.28], 156], ...}

问题是这些值是[[value1], value2]而不是[value1, value2]。

有人能帮忙吗？非常感谢。

Answer 1

这样的东西应该可以工作：

{key: [value] + flow.get(key, []) for key, value in dist.items()}

示例：

In [11]: dist
Out[11]: {(101, 15): 688, (47, 92): 156, (13, 62): 208}
In [12]: flow
Out[12]: {(49, 53): [122.92], (105, 34): [40.26], (47, 92): [85.28]}
In [13]: {key: [value] + flow.get(key, []) for key, value in dist.items()}
Out[13]: {(101, 15): [688], (47, 92): [156, 85.28], (13, 62): [208]}

Answer 2

flow_dist = flow.copy()
for x in flow:
if x in dist:
flow_dist[x].append(dist[x])