无法在iOS上为arm64构建webtc

Question

我正在尝试制作一个WebRTC。

这是我运行来构建它。

gn gen out/ios_arm64device --args='target_os="ios" target_cpu="arm64" ios_code_signing_identity="********" ios_code_signing_identity_description=""'
ninja -C out/ios_arm64device sdk:framework_objc
xcodebuild -create-xcframework -framework out/is_arm64device/WebRTC.framework -output out/arm64/WebRTC.xcframework

然而，在我添加了WebRTC。当我试图运行它时，我得到以下错误:

Undefined symbols for architecture arm64:
"_OBJC_CLASS_$_RTCPeerConnectionFactory", referenced from:
objc-class-ref in RTIWebRTCClient.o
"_OBJC_CLASS_$_RTCDefaultVideoDecoderFactory", referenced from:
objc-class-ref in RTIWebRTCClient.o
"_OBJC_CLASS_$_RTCDefaultVideoEncoderFactory", referenced from:
objc-class-ref in RTIWebRTCClient.o
"_RTCInitializeSSL", referenced from:
-[RTIWebRTCClient configure] in RTIWebRTCClient.o
ld: symbol(s) not found for architecture arm64
clang: error: linker command failed with exit code 1 (use -v to see invocation)

你知道我错过了什么吗?

Answer 1

在您的gn gen中添加参数rtc_enable_symbol_export=true并再次生成您的框架，它应该可以工作。

gn gen out/ios_arm64device --args='target_os="ios" target_cpu="arm64" ios_code_signing_identity="********" ios_code_signing_identity_description=""'