Kotlin编辑文本;电话号码的短信监视器

Question

我试图在我的项目中从editText获得一个电话号码。我遇到的问题;

1→第一个数字不应该是0。2→可惜我不能删除空格。

我想要的数字格式;(555) 555 55 55我的代码所处的阶段;

class PhoneNumberMask(val editText: EditText) : TextWatcher {
var phoneNumber: String = ""
var isRunning: Boolean = false
override fun beforeTextChanged(s: CharSequence?, start: Int, count: Int, after: Int) {
}
override fun onTextChanged(s: CharSequence?, start: Int, before: Int, count: Int) {
}
override fun afterTextChanged(s: Editable) {
if (isRunning || s.length == 15) {
return
}
isRunning = true
phoneNumber = when (s.length) {
0 -> "test"
1 -> "($s"
4 -> "$s) "
9 -> "$s "
12 -> "$s "
else -> s.toString()
}
editText.setText(phoneNumber).also { editText.setSelection(phoneNumber.length) }
isRunning = false
}
}

Answer 1

我认为当用户将光标移动到文本字段的中间、退格或试图粘贴文本时，您的策略将会遇到麻烦。我要尝试的是每次更改时只过滤数字，并每次为整个数字字符串插入括号/空格。然后把光标放回原来的位置。你可以从onTextChanged中比从afterTextChanged中更容易地找出光标应该在哪里。

像这样:

class PhoneNumberMask(val editText: EditText) : TextWatcher {
private var isRunning: Boolean = false
override fun beforeTextChanged(s: CharSequence, start: Int, count: Int, after: Int) {
}
override fun onTextChanged(s: CharSequence, start: Int, before: Int, count: Int) {
if (isRunning) {
return
}
var cursorPosition = start + count
val digits = s.filter(Char::isDigit)
.dropWhile { it == '0' }
.take(10)
cursorPosition -= s.take(cursorPosition).run {
count { !it.isDigit() } + filter(Char::digit).takeWhile { it == '0' }.count()
}
val output = StringBuilder(digits)
fun punctuate(position: Int, punctuation: String) {
if (digits.length > position) {
output.insert(position, punctuation)
if (cursorPosition > position) {
cursorPosition += punctuation.length
}
}
}
punctuate(8, " ")
punctuate(6, " ")
punctuate(3, ") ")
punctuate(0, "(")
isRunning = true
editText.setText(output)
editText.setSelection(cursorPosition.coerceAtMost(output.length))
isRunning = false
}
override fun afterTextChanged(s: Editable) {
}
}