有一个随机分布的表
CREATE TABLE schema.table (
col1 int4 NULL,
col2 int4 NULL,
col3 int4 NULL
)
WITH (
appendonly=true,
compresstype=zstd,
orientation=column
)
DISTRIBUTED RANDOMLY;
我们需要最优地(以最小的倾斜)将行分布在一个字段上。为此,我们可以创建测试表
CREATE TABLE schema.test_table (
col_1 int4 NULL,
col_2 int4 NULL,
col_3 int4 NULL
)
WITH (
appendonly=true,
compresstype=zstd,
orientation=column
)
DISTRIBUTED BY (col_i);
INSERT INTO schema.test_table SELECT * FROM schema.table;
然后检查它们是否歪斜,例如通过
select * from gp_toolkit.gp_skew_coefficient('schema.test_table'::regclass);
问题是我们想要在不创建测试表的情况下检查表的倾斜。这可以做到吗?如果可以,如何做到?
如果您真的不想创建一个新表,那么这样做是可以的,但是我不知道有什么方法可以在不实际(重新)分布数据的情况下对分布进行建模。
foo=# create table foo(a int, b int, c int);
NOTICE: Table doesn't have 'DISTRIBUTED BY' clause -- Using column named 'a' as the Greenplum Database data distribution key for this table.
HINT: The 'DISTRIBUTED BY' clause determines the distribution of data. Make sure column(s) chosen are the optimal data distribution key to minimize skew.
CREATE TABLE
foo=# insert into foo values (generate_series(1,100), generate_series(101,200), generate_series(2001, 2100));
INSERT 0 100
foo=# select * from gp_toolkit.gp_skew_coefficient('public.foo'::regclass);
skcoid | skccoeff
--------+--------------------------
76788 | 18.460769214742921763000
(1 row)
foo=# select gp_segment_id, count(*) from foo group by 1 order by 1;
gp_segment_id | count
---------------+-------
0 | 17
1 | 18
2 | 23
3 | 17
4 | 15
5 | 10
(6 rows)
foo=# ALTER TABLE foo SET
foo-# WITH (REORGANIZE=true)
foo-# DISTRIBUTED BY (a);
ALTER TABLE
foo=# select * from gp_toolkit.gp_skew_coefficient('public.foo'::regclass);
skcoid | skccoeff
--------+--------------------------
76788 | 18.460769214742921763000
(1 row)
foo=# select gp_segment_id, count(*) from foo group by 1 order by 1;
gp_segment_id | count
---------------+-------
0 | 21
1 | 18
2 | 12
3 | 15
4 | 18
5 | 16
(6 rows)
foo=#
foo=# ALTER TABLE foo SET
WITH (REORGANIZE=true)
DISTRIBUTED BY (b);
ALTER TABLE
foo=# select * from gp_toolkit.gp_skew_coefficient('public.foo'::regclass);
skcoid | skccoeff
--------+--------------------------
76788 | 27.011108825814611346000
(1 row)
foo=# select gp_segment_id, count(*) from foo group by 1 order by 1;
gp_segment_id | count
---------------+-------
0 | 12
1 | 14
2 | 20
3 | 24
4 | 16
5 | 14
(6 rows)
foo=#
foo=# ALTER TABLE foo SET
WITH (REORGANIZE=true)
DISTRIBUTED BY (c);
ALTER TABLE
foo=# select * from gp_toolkit.gp_skew_coefficient('public.foo'::regclass);
skcoid | skccoeff
--------+--------------------------
76788 | 30.983866769659334938000
(1 row)
foo=#
foo=# select gp_segment_id, count(*) from foo group by 1 order by 1;
gp_segment_id | count
---------------+-------
0 | 19
1 | 10
2 | 20
3 | 23
4 | 11
5 | 17
(6 rows)
foo=#