青梅分布



有一个随机分布的表

CREATE TABLE schema.table (
col1 int4 NULL,
col2 int4 NULL,
col3 int4 NULL
)
WITH (
appendonly=true,
compresstype=zstd,
orientation=column
)
DISTRIBUTED RANDOMLY; 

我们需要最优地(以最小的倾斜)将行分布在一个字段上。为此,我们可以创建测试表

CREATE TABLE schema.test_table (
col_1 int4 NULL,
col_2 int4 NULL,
col_3 int4 NULL
)
WITH (
appendonly=true,
compresstype=zstd,
orientation=column
)
DISTRIBUTED BY (col_i); 
INSERT INTO schema.test_table SELECT * FROM schema.table;

然后检查它们是否歪斜,例如通过

select * from gp_toolkit.gp_skew_coefficient('schema.test_table'::regclass);

问题是我们想要在不创建测试表的情况下检查表的倾斜。这可以做到吗?如果可以,如何做到?

如果您真的不想创建一个新表,那么这样做是可以的,但是我不知道有什么方法可以在不实际(重新)分布数据的情况下对分布进行建模。

foo=# create table foo(a int, b int, c int);
NOTICE:  Table doesn't have 'DISTRIBUTED BY' clause -- Using column named 'a' as the Greenplum Database data distribution key for this table.
HINT:  The 'DISTRIBUTED BY' clause determines the distribution of data. Make sure column(s) chosen are the optimal data distribution key to minimize skew.
CREATE TABLE
foo=# insert into foo values (generate_series(1,100), generate_series(101,200), generate_series(2001, 2100));
INSERT 0 100
foo=# select * from gp_toolkit.gp_skew_coefficient('public.foo'::regclass);
skcoid |         skccoeff
--------+--------------------------
76788 | 18.460769214742921763000
(1 row)
foo=# select gp_segment_id, count(*) from foo group by 1 order by 1;
gp_segment_id | count
---------------+-------
0 |    17
1 |    18
2 |    23
3 |    17
4 |    15
5 |    10
(6 rows)

foo=# ALTER TABLE foo SET
foo-# WITH (REORGANIZE=true)
foo-# DISTRIBUTED BY (a);
ALTER TABLE
foo=# select * from gp_toolkit.gp_skew_coefficient('public.foo'::regclass);
skcoid |         skccoeff
--------+--------------------------
76788 | 18.460769214742921763000
(1 row)
foo=# select gp_segment_id, count(*) from foo group by 1 order by 1;
gp_segment_id | count
---------------+-------
0 |    21
1 |    18
2 |    12
3 |    15
4 |    18
5 |    16
(6 rows)
foo=#
foo=# ALTER TABLE foo SET
WITH (REORGANIZE=true)
DISTRIBUTED BY (b);
ALTER TABLE
foo=# select * from gp_toolkit.gp_skew_coefficient('public.foo'::regclass);
skcoid |         skccoeff
--------+--------------------------
76788 | 27.011108825814611346000
(1 row)
foo=# select gp_segment_id, count(*) from foo group by 1 order by 1;
gp_segment_id | count
---------------+-------
0 |    12
1 |    14
2 |    20
3 |    24
4 |    16
5 |    14
(6 rows)
foo=#

foo=# ALTER TABLE foo SET
WITH (REORGANIZE=true)
DISTRIBUTED BY (c);
ALTER TABLE
foo=# select * from gp_toolkit.gp_skew_coefficient('public.foo'::regclass);
skcoid |         skccoeff
--------+--------------------------
76788 | 30.983866769659334938000
(1 row)
foo=#
foo=# select gp_segment_id, count(*) from foo group by 1 order by 1;
gp_segment_id | count
---------------+-------
0 |    19
1 |    10
2 |    20
3 |    23
4 |    11
5 |    17
(6 rows)
foo=#

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