计算一个向量中连续出现的次数

Question

我有以下向量:

vec <- c(28, 44, 45, 46, 47, 48, 61, 62, 70, 71, 82, 83, 104, 105, 111, 115, 125, 136, 137, 138, 146, 147, 158, 159, 160, 185, 186, 187, 188, 189, 190, 191, 192, 193, 209, 263, 264, 265, 266, 267, 268, 280, 283, 284, 308, 309, 318, 319, 324, 333, 334, 335, 347, 354)

现在我想要得到最小长度为2的向量中连续出现的次数。因此，在以下情况下，这是有效的:

44, 45, 46, 47, 48
61, 62
70, 71
82, 83
104, 105
136, 137, 138
146, 147
158, 159, 160
185, 186, 187, 188, 189, 190, 191, 192, 193
263, 264, 265, 266, 267, 268
283, 284
308, 309
318, 319
333, 334, 335

所以有14个连续的数字，我只需要整数14作为输出。

有人知道怎么做吗?

Answer 1

可以使用rle和diff函数:

a=rle(diff(vec))
sum(a$values==1)

Answer 2

diff和split将有所帮助

vec2 <- split(vec, cumsum(c(1, diff(vec) != 1)))
vec2[(sapply(vec2, function(x) length(x))>1)]
$`2`
[1] 44 45 46 47 48
$`3`
[1] 61 62
$`4`
[1] 70 71
$`5`
[1] 82 83
$`6`
[1] 104 105
$`10`
[1] 136 137 138
$`11`
[1] 146 147
$`12`
[1] 158 159 160
$`13`
[1] 185 186 187 188 189 190 191 192 193
$`15`
[1] 263 264 265 266 267 268
$`17`
[1] 283 284
$`18`
[1] 308 309
$`19`
[1] 318 319
$`21`
[1] 333 334 335

Answer 3

强制:

var <- sort(var)
nconsecutive <- 0
p <- length(var)-1
for (i in 1:p){
if((var[i + 1] - var[i]) == 1){
consecutive <- consecutive + 1
}else{
# If at least one consecutive number
if(consecutive > 0){
# when no more consecutive numbers add one to your increment
nconsecutive = nconsecutive + 1
}
# Re set to 0 your increment
consecutive <- 0
}
}

Answer 4

下面是另一个使用tapply-

的base R一行代码

sum(tapply(vec, cumsum(c(TRUE, diff(vec) != 1)), length) > 1)
#[1] 14