Android -将XML解析为JSON

Question

我的用例要求我获取如下格式的XML，并需要将其映射到JSON对象:

<settings>
<client ip="......" lat="...." lon="...." isp="...." country="...."/>
<translation lang="xml"> </translation>
</settings>

我使用Retrofit与Moshi作为转换器工厂的请求:

Retrofit.Builder()
.addConverterFactory(MoshiConverterFactory.create(moshi).asLenient())
.baseUrl(BASE_URL)
.client(okHttpClient)
.build()

我尝试在SimpleXml的帮助下创建响应模型(com.squareup.retrofit2:converter-simplexml:2.9.0)但到目前为止还没有运气。我一直得到这个错误:

com.squareup.moshi。JsonDataException:期望的BEGIN_OBJECT，但在路径$

是STRING

任何人可能有一个想法如何将这个结构映射到Json?提前感谢!

反应模型:

@Root(name = "settings", strict = false)
data class ConfigurationEntity(
@field:Attribute(name = "client", required = false)
@param:Attribute(name = "client", required = false)
val client: ClientEntity?
)

@Root(name = "client")
data class ClientEntity(
@field:Attribute(name = "ip", required = false)
@param:Attribute(name = "ip", required = false)
val ip: String?,
@field:Attribute(name = "lat", required = false)
@param:Attribute(name = "lat", required = false)
val lat: String?,
@field:Attribute(name = "lon", required = false)
@param:Attribute(name = "lon", required = false)
val lon: String?,
@field:Attribute(name = "isp", required = false)
@param:Attribute(name = "isp", required = false)
val isp: String?,
@field:Attribute(name = "country", required = false)
@param:Attribute(name = "country", required = false)
val country: String?
)

<<p>解决方案/strong>

改造施工:

Retrofit.Builder()
.addConverterFactory(SimpleXmlConverterFactory.create())
.baseUrl(BASE_URL)
.client(okHttpClient)
.build()

模型:

@Root(name = "settings", strict = false)
class ConfigurationEntity {
@field:Element(required = false)
lateinit var client: ClientEntity
}

@Root(name = "client", strict = false)
class ClientEntity {
@field:Attribute
lateinit var ip: String
@field:Attribute
lateinit var lat: String
@field:Attribute
lateinit var lon: String
@field:Attribute
lateinit var isp: String
@field:Attribute
lateinit var country: String
}

这个链接也可能是有用的Kotlin -解析Xml响应与列表使用SimpleXml

Answer 1

您需要将此转换器工厂添加到您的Retrofit Builder -

Retrofit.Builder()
.addConverterFactory(SimpleXmlConverterFactory.create())

这允许Retrofit解释它正在获取的XML，并将其转换为等效的JSON数据对象。