Curl这是成功的工作。如何将其转换为Python请求?
curl -i -X POST
-H "Content-Type:multipart/form-data"
-H "Authorization: Bearer <your-access-token>"
-H "service-account-id: <your-service-account-id>"
-F "file=@"./ICON_512x512.png";type=image/png;filename="ICON_512x512.png""
-F "sessionId=<session-id>"
"https://seller.samsungapps.com/galaxyapi/fileUpload"
我的Python代码有什么问题?
headers = {"Content-Type": "multipart/form-data", "Authorization": "Bearer " + <your-access-token>,
"service-account-id": <your-service-account-id>}
files = {
"file": open("./ICON_512x512.png", "rb"),
"type": "image/png",
"filename": "ICON_512x512.png",
'sessionId': <session-id>
}
response = requests.post("https://seller.samsungapps.com/galaxyapi/fileUpload",
headers=headers,
files=files)
您必须将文件属性嵌套在自己的元组中,如文档中所述。
试试这个。
import requests
headers = {
'Content-Type': 'multipart/form-data',
'Authorization': 'Bearer <your-access-token>',
'service-account-id': '<your-service-account-id>',
}
files = {
'file': ('./ICON_512x512.png', open('./ICON_512x512.png', 'rb')),
'sessionId': '<session-id>',
}
response = requests.post('https://seller.samsungapps.com/galaxyapi/fileUpload', headers=headers, files=files)