根据匹配的属性合并两个对象数组

Question

我有两个带有部分信息的数组，我希望将这些带有所有信息的数组合并为一个数组。

阵列1:

const arr1 = [
{
name: 'Rohan',
surname: 'Mehra',
age: '15',
date: "2021-01-19",
location: 'Goa'
},
{
name: 'Aman',
surname: 'Kohli',
age: '14',
date: "2021-01-19",
location: 'Kolkata'
},
{
name: 'Sam',
surname: 'Sharma',
age: '16',
date: "2021-01-21",
location: 'Mumbai'
}
]

阵列2:

const arr2 = [
{
rollNo: 1,
marks: 100,
name: 'Rohan',
date: "2021-01-19",
},
{
rollNo: 2,
marks: 90,
surname: 'Kohli',
date: "2021-01-19",
},
{
rollNo: 3,
marks: 70,
date: "2021-01-21",
ExamCenter: {
place: 'Mumbai'
}
}
]

我想从两个数组中得到一个具有属性的最终数组。Object键有时会更改，我想将该键与另一个通用键匹配并合并它们。但我无法继续解决问题。这是我想要得到的结果数组。

const final = [
{
name: 'Rohan',
surname: 'Mehra',
age: '15',
date: "2021-01-19",
location: 'Goa',
rollNo: 1,
marks: 100,
},
{
name: 'Aman',
surname: 'Kohli',
age: '14',
date: "2021-01-19",
location: 'Kolkata',
rollNo: 2,
marks: 90,
},
{
name: 'Sam',
surname: 'Sharma',
age: '16',
date: "2021-01-21",
location: 'Mumbai',
rollNo: 3,
marks: 70,
}
]

我正在尝试嵌套映射循环，但无法进行

const final = arr1.map((item,index) => {
arr2.map((innerItem, i) => {
if(item[Object.keys(innerItem)][index] === innerItem[Object.keys(innerItem)][0]){
console.log(item);
}
})
})

Answer 1

您的arr2中有一个错误。第二项的姓氏应为kohli，而不是kolhi。无论如何，您可以根据动态匹配属性执行以下操作来合并两个数组。我们在这里做的是，

对于arr1的每个项目，我们使用Object.keys方法找到密钥，并检查来自arr2的哪个对象与arr1的项目具有最大匹配对象。然后我们把这两个项目合并在一起。

arr1 = [
{
name: 'Rohan',
surname: 'Mehra',
age: '15',
date: "2021-01-19",
location: 'Goa'
},
{
name: 'Aman',
surname: 'Kohli',
age: '14',
date: "2021-01-19",
location: 'Kolkata'
},
{
name: 'Sam',
surname: 'Sharma',
age: '16',
date: "2021-01-21",
location: 'Mumbai'
}
]
arr2 = [
{
rollNo: 1,
marks: 100,
name: 'Rohan',
date: "2021-01-19",
},
{
rollNo: 2,
marks: 90,
surname: 'Kohli',
date: "2021-01-19",
},
{
rollNo: 3,
marks: 70,
date: "2021-01-21",
ExamCenter: {
place: 'Mumbai'
}
}
]
res = arr1.map(item => {
keys1 = Object.keys(item);
let max = 0;
const temp = arr2.reduce((prev, item2) => {
maxTemp = keys1.filter(key => item[key] === item2[key]).length;
if(maxTemp > max) {
max = maxTemp;
prev = item2;
}
return prev;
}, {})

if(temp) {
return {...item, ...temp}
}
});
console.log(res);

Answer 2

您可以执行这样的操作来合并两个数组。

const arr1 = [
{
name: 'Rohan',
surname: 'Mehra',
age: '15',
date: "2021-01-19",
location: 'Goa'
},
{
name: 'Aman',
surname: 'Kohli',
age: '14',
date: "2021-01-19",
location: 'Kolkata'
},
{
name: 'Sam',
surname: 'Sharma',
age: '16',
date: "2021-01-21",
location: 'Mumbai'
}
]
const arr2 = [
{
rollNo: 1,
marks: 100,
name: 'Rohan',
date: "2021-01-19",
},
{
rollNo: 2,
marks: 90,
surname: 'Kolhi',
date: "2021-01-19",
},
{
rollNo: 3,
marks: 70,
date: "2021-01-21",
ExamCenter: {
place: 'Mumbai'
}
}
]
const newArray = [];
arr2.forEach((item) => {
const array1Item = arr1.find(({ date }) => date === item.date);

if (array1Item) {
newArray.push({
...item,
...array1Item,
})
}
})
console.log(newArray);

Answer 3

这可能有助于

const arr3 = arr1.map((value, index) => {
return Object.assign(value, arr2[index])
})