如何使用rumel .yaml读取多个yaml定义

Question

是否可以从单个文件中读取多个yaml定义?

示例代码:

import ruamel.yaml
text = '''
---
foo: bar
---
baz: baz
...
'''
yaml = ruamel.yaml.YAML(typ='rt')
yamlFile = yaml.load(text)

预期行为类似于:

for i in yamlFile:
print(i) #foo: bar, baz: baz

实际行为是:

Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/Users/bruno.miranda/Desktop/iac/iac-wrapper/venv/lib/python3.9/site-packages/ruamel/yaml/main.py", line 434, in load
return constructor.get_single_data()
File "/Users/bruno.miranda/Desktop/iac/iac-wrapper/venv/lib/python3.9/site-packages/ruamel/yaml/constructor.py", line 120, in get_single_data
node = self.composer.get_single_node()
File "/Users/bruno.miranda/Desktop/iac/iac-wrapper/venv/lib/python3.9/site-packages/ruamel/yaml/composer.py", line 81, in get_single_node
raise ComposerError(
ruamel.yaml.composer.ComposerError: expected a single document in the stream
in "<unicode string>", line 3, column 1:
foo: bar
^ (line: 3)
but found another document
in "<unicode string>", line 4, column 1:
---

也尝试没有typ='rt'的构造函数，但我有相同的结果。

我使用的版本是:

pip show ruamel.yaml
Name: ruamel.yaml
Version: 0.17.16

Answer 1

除了.load()，还有.load_all()，它为所有加载的数据提供了一个迭代器，每个文档一个。

yaml = ruamel.yaml.YAML()
for data in yaml.load_all():
do_your_thing_with(data)