regex或任何js字符串方法从url中获取文本

Question

如何只获取此文本

abc-test-bucket.s3.ap-south-1.amazonaws.com/test-Service/0022JUN_29O00190_126072.pdf

从这个url

https://s3.ap-south-1.amazonaws.com/abc-test-bucket/test-service/https%3A/%2Fabc-test-bucket.s3.ap-south-1.amazonaws.com/test-Service/0022JUN_29O00190_126072.pdf

Answer 1

使用regex肯定有更有效的方法可以做到这一点。

此方法假设最后一个带有%符号的查询参数有2个字符，我们使用substring((删除这些字符

const inputString = "https://s3.ap-south-1.amazonaws.com/abc-test-bucket/test-service/https%3A/%2Fabc-test-bucket.s3.ap-south-1.amazonaws.com/test-Service/0022JUN_29O00190_126072.pdf";
let subs = inputString.split("%");
let whatWeWant = subs[subs.length-1].substring(2);
console.log(whatWeWant);