迭代的API调用，直到找到结尾

Question

我有一个API，它返回有限的数据结果极限值不能大于1000

> https://api.source.com?start=0&limit=1000 //first call
> https://api.source.com?start=1001&limit=1000 //second call
> https://api.source.com?start=2001&limit=1000 //third call
> https://api.source.com?start=3001&limit=1000 //fourth call
{
"success": true,
"message": "Verticals Returned",
"response": {
"start": 0,
"limit": 1000,
"returned": 1000,
"total": 3230,
"data": [
{
"verticalID": 3,
"verticalName": "Galaxies",
"status": "Active",
"groupID": 1,
"createdOn": "2022-03-15 05:30:06",
"groupName": "Solar",
"totalOffers": 0
}
]
}
}

它是如何使用循环来迭代的？同时或任何其他循环也可以。

我试过

limit =1000
start = 0;
total = undefined;
for(i=start;;i+=returned)
{
y = call("https://api.source.com?start="+start+"&limit="+limit)
total = y.total
start = y.start
returned = y.returned
}

Answer 1

const apiLoop = async () =>{
let counter = 0;
const limit = 1000;
while (true) {
try{
let y = await call("https://api.source.com?start="+(counter*limit)+"&limit="+limit);
if(y==null)  
break;
counter++;
}
catch(e){
console.log(e.message);
break;
}
}
}
apiLoop();

根据y变量的值，当start查询参数大于总长度时，打破循环的条件将有所不同。这里我假设y应该是null。请注意，call函数应为async，并在此代码块中等待。因为迭代中的每个API调用都应该首先得到结果，然后根据结果，函数决定是否继续while循环。