在vim中创建1列中的2列

Question

我有两个很长的串联数组:

["MyHashMap"
"remove"
"put"
"remove"]
[[]
[27]
[65,65]
[19]]

我只是进入可视化模式，y第二个数组，然后回到第一行，到它的末尾，添加空格并点击p。它变成:

["MyHashMap"
[[]
[27]
[65,65]
[19]]
"remove"
"put"
"remove"]

我想要的输出是:

["MyHashMap" [[]
"remove"     [27]
"put"        [65,65]
"remove"]    [19]]

我怎样才能做到这一点?

Answer 1

:set virtualedit=all，这样您就可以将光标移动到没有字符的地方(超过行尾)。

将光标移动到第5行第一列，并使用CTRL-V进入视觉块模式。选择最后四行的内容。按d删除所选内容。

将光标移动到第一行，即第二列所在的位置。按p粘贴

Answer 2

所以…返回到原始数据格式(为了完整性，我添加了一个额外的"行"):

数据如下:

$ cat yuck
["MyHashMap","remove","put","put"]
["MyMashNap","mover","gut","hut"]
[[],44],[95,30]]

下面是awk脚本:

$ cat a.f 
BEGIN{
FS=","
}
{
for (f = 1; f <= NF; f++) { a[NR, f] = $f } 
}
NF > nf { nf = NF }
END {
for (f = 1; f <= nf; f++) {
for (r = 1; r <= NR; r++) {
printf a[r, f] (r==NR ? RS : OFS)
}
}
}

和如何运行它:

$ awk  -f a.f yuck  | column -t
["MyHashMap"  ["MyMashNap"  [[]
"remove"      "mover"       44]
"put"         "gut"         [95
"put"]        "hut"]        30]]

Answer 3

使用视觉块选择:

如果你在第一行:

4j ............. jump to line five 
Ctrl-v ......... start visual block
3j$ ............ select the end of the paragraph
dgg ............ delete and goes to the first line
A<Space> ....... add an extra space
<Esc>p ......... paste deleted block