使用for循环计算字典中所有值的和，不使用sum()函数

Question

使用for循环计算这个字典中值的总和，不使用sum()函数?

Dictionary = {"001": {"a" : [1, 5, 6], "b" : [2, 8, 9] }, "002": {"c" : [6.89, 5.67, 1.24], "d" : [9.32, 6, 78] }}

我试着回答这个问题在许多方法，但我总是得到这个错误:

TypeError: unsupported operand type(s) for +: 'int' and 'dict'

谢谢你!

Answer 1

根据数据结构使用嵌套循环:

total = 0
for dct in Dictionary.values():  # the outermost dict's values are dicts again ...
for lst in dct.values():     # ... whose values are lists ...
for num in lst:          # ... whose elements are addable numbers
total += num
total
# 138.12

Answer 2

我想你是想用操作数+对字典求和相反，你需要获取列表中的每一个数字(提醒一下，列表在一个字典中，而这个字典在另一个字典中)所以我写了一个for循环:

Dictionary = {"001": {"a": [1, 5, 6], "b": [2, 8, 9]}, "002": {"c": [6.89, 5.67, 1.24], "d": [9.32, 6, 78]}}
for c in range(0, len(Dictionary['001'])):
l1 = Dictionary['001']['a']
l2 = Dictionary['001']['b']
som1 = l1[c] + l2[c]
for c in range(0, len(Dictionary['002'])):
l1 = Dictionary['002']['c']
l2 = Dictionary['002']['d']
som2 = l1[c] + l2[c]
somt = som1 + som2
print(somt)