枚举的JPA规范

Question

我的JPA实体作为Enum字段

@Table(name="zsrb_ordini_prod")
@Entity
@JsonIgnoreProperties(ignoreUnknown = true)
public class OrdineProd implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
public Long idOrdineProd;
...
@Enumerated(EnumType.STRING)
public StOrdine stato = StOrdine.CREATO;
...
}

,

public enum StOrdine {
CREATO,
SCHEDULATO,
CONFERMATO,
SCARTATO
}

如果我用规范

添加where条件

Specification<OrdineProd> = (root, query, qb)->
qb.equal(root.get("stato"), StOrdine.SCHEDULATO);

java.lang.IllegalArgumentException: Parameter value [SCHEDULATO] did not match expected type [imp.srb.progettazione.ordProd.StOrdine (n/a)]
at org.hibernate.query.spi.QueryParameterBindingValidator.validate(QueryParameterBindingValidator.java:54) ~[hibernate-core-5.4.9.Final.jar:5.4.9.Final]
at org.hibernate.query.spi.QueryParameterBindingValidator.validate(QueryParameterBindingValidator.java:27) ~[hibernate-core-5.4.9.Final.jar:5.4.9.Final]
...

在规范查询中包含枚举的正确方法是什么?

Answer 1

试着这样做:

Specification<OrdineProd> = (root, query, qb) ->
qb.equal(root.get("stato"), StOrdine.SCHEDULATO.name);