我有一个名为stock
的Mysql表,查询返回item_id = 271
的总库存。
select sum(qty) from stock where item_id = 271;
+----------+
| sum(qty) |
+----------+
| 127.00 |
+----------+
1 row in set (0.001 sec)
但是在我的原始查询中,我无法获得item_id
的正确股票值。
这是我的查询:
SELECT p.purchase_id
, p.reference_number
, pi.item_id
, pi.received_qty
, pi.cost_price_before_disc
, pi.item_discount
, round(pi.received_qty * pi.cost_price_after_disc, 2) as inline_total
, sum(current_stock) as stock
FROM purchase_draft p
JOIN purchase_item_draft pi USING(purchase_id)
JOIN item i ON pi.item_id = i.item_id
LEFT JOIN (
SELECT p.purchase_id
, pi.item_id
, sum(ifnull(s.qty, 0)) as current_stock
FROM purchase_draft p
LEFT JOIN purchase_item_draft pi USING(purchase_id)
LEFT JOIN stock s ON s.item_id = pi.item_id ANd qty_type = 'a'
GROUP BY pi.item_id, p.purchase_id
) s ON s.item_id = pi.item_id
WHERE p.purchase_id = 4
GROUP BY purchase_id, pi.item_id
+-------------+------------------+---------+--------------+------------------------+---------------+--------------+--------+
| purchase_id | reference_number | item_id | received_qty | cost_price_before_disc | item_discount | inline_total | stock |
+-------------+------------------+---------+--------------+------------------------+---------------+--------------+--------+
| 4 | PO2022/0004 | 92 | 60 | 1285.00 | 0.00 | 77100.00 | 0.00 |
| 4 | PO2022/0004 | 271 | 40 | 3396.00 | 0.05 | 135838.00 | 254.00 |
| 4 | PO2022/0004 | 407 | 10 | 3100.00 | 500.00 | 26000.00 | 0.00 |
| 4 | PO2022/0004 | 582 | 30 | 2898.00 | 0.21 | 86933.70 | 0.00 |
| 4 | PO2022/0004 | 583 | 20 | 1552.50 | 1.33 | 31023.40 | 0.00 |
| 4 | PO2022/0004 | 640 | 15 | 3285.00 | 2.00 | 49245.00 | 0.00 |
+-------------+------------------+---------+--------------+------------------------+---------------+--------------+--------+
6 rows in set (0.002 sec)
我能知道我在查询中做错了什么吗?
您需要在join中聚合股票表。
替换:
LEFT JOIN stock s ON s.item_id = pi.item_id ANd qty_type = 'a'
:
LEFT JOIN (
SELECT item_id, sum(qty) AS qty
FROM stock
WHERE qty_type = 'a'
GROUP BY item_id
) s ON s.item_id = pi.item_id