检查字符串是否包含python字典中的单词

Question

我只想检查给定字符串是否包含字典中的单词

names = ["Joe", "Smith", "Nancy"]

string = "Her name was Nancy"
if names in string:
print(name)

对于本例，我希望它输出名称'Nancy'

Answer 1

你好，我想这可以解决你的问题:

string = "Her name was Nancy"
names = ["Joe", "Smith", "Nancy"]
for name in names:
if name in string:
print("True")

Answer 2

您可以使用re:

import re
names = ["Joe", "Smith", "Nancy"]
string = "Her name was Nancy. His name was Smith"
result = re.findall('|'.join(names), string)
print(*result, sep='n')

---

Nancy
Smith

Answer 3

有几点。首先，names是一个列表而不是字典，而string恰好是一个字符串。所以在你提供的代码中没有字典。无论如何，看起来您想要查看列表中的元素是否包含在字符串中。为此，您应该遍历列表，然后检查每个元素是否在目标字符串内。然后，您可以简单地打印匹配项。

names = ["Joe", "Smith", "Nancy"]
string = "Her name was Nancy"
for name in names:
if name in string:
print(name)

Answer 4

您可以使用带有生成器表达式和可选默认值的next执行以下操作:

name = next((n for n in names if n in string), None)
print(name)

,

x = next(iterator, default)

是以下习语的简写:

for x in iterator:
break        # take the first if present 
else:
x = default  # or fallback

如果您只想匹配字符串中的整个单词(令牌)，您可能需要先将其str.split:

tokens = set(string.split())  # set has a better contains-check
name = next((n for n in names if n in tokens) , None)

一些文档:

• next
• set
• str.split
• for-else andbreak
<
• 生成器表达式/gh>

Answer 5

python列表推导语法:

[print(name) for name in names if name in string]

如果你想把结果存储在var中:

res = [name for name in names if name in string]

Answer 6

根据您所写的内容，names不是字典，而是数组。假设names确实是一个数组，这应该可以满足您的要求。

names = ["Joe", "Smith", "Nancy"]

string = "Her name was Nancy"
for name in names:
if names in string:
print(name)