Python bingo project

Question

所以我的代码的设计基本上是创建一个宾果牌，然后当你按下回车绘制一个数字，并改变宾果牌值为0，如果绘制的数字匹配。我的问题是，我的代码没有正确地产生宾果或不是宾果，你可以看到在代码的末尾。我应该如何改变这一点，使我的代码将返回bingo当我有bingo。

import random #Condernsed solo version with call and player together
import numpy as np
def bingo_card(): #Code to generate BINGO card using numpy array
test1=np.array(random.sample(range(1,16),5))
test2=np.array(random.sample(range(16,31),5))
test3=np.array(random.sample(range(31,46),5))
test4=np.array(random.sample(range(46,61),5))
test5=np.array(random.sample(range(61,76),5))
test= np.concatenate((test1,test2,test3,test4,test5))
test= test.reshape(5,5)
test[2,2]=0
bingo_card.test = test
BINGO= print("Your Card")
print("B", test[0]),
print("I", test[1]), 
print("N", test[2]), 
print("G", test[3]), 
print("O", test[4])
card = BINGO

return card
def called_value(): #should be close to the code we use to check if called value is in generated matrix, may need some formatting and fixing
checked_card = bingo_card.test
while True:
called_num = input ("Type called number to mark card or press 's' to quit if you think you have bingo").lower()
if called_num != "s":
number_check = int(called_num)
checked_card = np.where(checked_card==number_check,0,checked_card)
BINGO = print("Your Card")
print("B", checked_card[0]),
print("I", checked_card[1]), 
print("N", checked_card[2]), 
print("G", checked_card[3]), 
print("O", checked_card[4])
elif called_num == "s":
BINGO = print("Your Card")
print("B", checked_card[0]),
print("I", checked_card[1]), 
print("N", checked_card[2]), 
print("G", checked_card[3]), 
print("O", checked_card[4])
row_zeros = np.count_nonzero(checked_card == 0, axis=1)
col_zeros = np.count_nonzero(checked_card == 0, axis=0)
diagonal_zeros = np.count_nonzero(np.diag(checked_card) == 0)
diagonal1_zeros = np.count_nonzero(np.diag(np.fliplr(checked_card)) == 0)
for i in range (5):
if (row_zeros[i] or col_zeros[i]) == 5:
return ("Bingo!")
elif (diagonal_zeros or diagonal1_zeros) == 5:
return ("Bingo!")
else:
return ("Not Bingo")
def solo():
bingo_card()
called_value()
solo()

Answer 1

你犯了一个典型的错误。

for i in range (5):
if (row_zeros[i] or col_zeros[i]) == 5:
return ("Bingo!")
elif (diagonal_zeros or diagonal1_zeros) == 5:
return ("Bingo!")
else:
return ("Not Bingo")

row_zeros[i] or col_zeros[i]将为True或False(通常为True)，它永远不会等于5。你不需要循环来检查对角线。你需要:

if diagonal_zeros == 5 or diagonal1_zeros == 5:
return ("Bingo!")
for i in range (5):
if row_zeros[i] == 5 or col_zeros[i] == 5:
return ("Bingo!")
return ("Not Bingo")