对2D数组元素按降序排序

Question

假设我有一个长度为n的2D数组，是否有一种方法可以根据子数组的大小将2D数组按降序排序

例如:

{{"1","b","g"},{"e","3"},{"r","2","9","a"},{"2"}}

将成为:

{{"r","2","9","a"},{"1","b","g"},{"e","3"},{"2"}}

Answer 1

String tab[][] = new String[][]{{"1","b","g"},{"e","3"},{"r","2","9","a"},{"2"}};
String temp[];          
for (int i = 0; i <tab.length; i++) {     
for (int j = i+1; j <tab.length; j++) {     
if(tab[i].length < tab[j].length) {
temp = tab[i];    
tab[i] = tab[j];    
tab[j] = temp;    
}     
}     
}             
System.out.println(Arrays.deepToString(tab));

输出:[[r, 2, 9, a], [1, b, g], [e, 3], [2]]

Answer 2

这个问题需要更多的细节。

考虑到给定的数据结构是一个数组，它看起来像-

[["1","b","g"],["e","3"],["r","2","9","a"],["2"]]

要在python中对这个数组排序，请考虑下面给出的代码:-

a = [["1","b","g"],["e","3"],["r","2","9","a"],["2"]]
a.sort(key=len)

将根据子数组的长度对数组进行排序