如何使用两个按钮筛选表的列类型?

Question

我想过滤类型列，一个按钮过滤水生元素，另一个按钮过滤水生元素以外的所有元素

<button type="button" onclick="Aquatic()">Aquatic</button>    
<button type="button" onclick="NotAquatic()" >everything but aquatic</button>
<table class="table" >      
<thead>
<tr>                    
<th scope="col">Animal</th>
<th scope="col">Type </th>
</tr>
</thead>
<tbody id="" >
<tr>
<td>bat</td>
<td>aerial</td>
</tr>
<tr>
<td>Fish</td>
<td>Aquatic</td>
</tr>
<tr>
<td>Horse</td>
<td>Land</td>
</tr>
<tr>
<td>Shark</td>
<td>Aquatic</td>
</tr>
<tr>
<td>Elephant</td>
<td>Land</td>
</tr>        
<tr>
<td>Whale</td>
<td>Aquatic</td>
</tr>
<tr>
<td>dove</td>
<td>aerial</td>
</tr>
</tbody>
</table>

Answer 1

希望这能帮助你找到正确的方向!有一个filterTable函数，它可以获取所有的表行，并删除之前添加到显示中的任何内联样式更改。然后，我通过不包括术语的innerHTML内容过滤所有trs，并将所有这些trs设置为none

function filterTable(aquaShown) {
const trs = [...document.querySelectorAll("tbody tr")];
trs.forEach(tr => tr.style.display = "");
const hiddenTrs = aquaShown ? 
trs.filter(tr => !tr.innerHTML.includes("Aquatic")) :
trs.filter(tr => tr.innerHTML.includes("Aquatic"));
hiddenTrs.forEach(tr => tr.style.display = "none");
}
function aquatic() {
filterTable(true);
}
function nonaquatic() {
filterTable(false);
}

<button type="button" onclick="aquatic()">Aquatic</button>
<button type="button" onclick="nonaquatic()">Non-Aquatic</button>
<table class="table">
<thead>
<tr>
<th scope="col">Animal</th>
<th scope="col">Type </th>
</tr>
</thead>
<tbody id="">
<tr>
<td>Fish</td>
<td>Aquatic</td>
</tr>
<tr>
<td>Horse</td>
<td>Land</td>
</tr>
<tr>
<td>Shark</td>
<td>Aquatic</td>
</tr>
<tr>
<td>Elephant</td>
<td>Land</td>
</tr>
<tr>
<td>Whale</td>
<td>Aquatic</td>
</tr>
</tbody>
</table>

编辑根据注释中的进一步说明进行了重构