如果对象id在其他对象id中有自己的属性，则更改数组中的对象值

Question

这是我的数据

let a = [
{
"activityCode": "23",
"isValid": null
},
{
"activityCode": "28",
"isValid": null
},
{
"activityCode": "32",
"isValid": null
}
]
let b = [
{
"activityCode": "23",
"allocated": 3
},
{
"activityCode": "32",
"allocated": 2
}
]

我想更改"isValid"如果数组中的activityCode(a)具有相同的activityCode(b) &"isValid"如果数组中的activityCode(a)与activityCode(b)不相同，则为false，并且我需要的输出如下:

let a = [
{
"activityCode": "23",
"isValid": true
},
{
"activityCode": "28",
"isValid": false
},
{
"activityCode": "32",
"isValid": true
}
]

请帮帮我。谢谢。

Answer 1

试试这个:

a.forEach(element => {
element.isValid = b.some(e => e.activityCode === element.activityCode);
});
console.log(a);

Answer 2

a.map(aa => {
const match = b.find(bb => bb.activityCode === aa.activityCode);
return { activityCode: aa.activityCode, isValid: match !== undefined };
})

Answer 3

您可以使用Array.map()和Array.some()来获得所需的结果。如果数组b中存在a中的任何元素array .some()将返回true。

let a = [ { "activityCode": "23", "isValid": null }, { "activityCode": "28", "isValid": null }, { "activityCode": "32", "isValid": null } ]
let b = [ { "activityCode": "23", "allocated": 3 }, { "activityCode": "32", "allocated": 2 } ]
const result = a.map(({ activityCode }) => ({ activityCode, isValid: b.some(el => el.activityCode === activityCode ) }));
console.log('Result:', result)

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