如何在python中运行一个函数的变量到另一个?

Question

我是初学者。我有两个功能:首先创建数据帧和一些打印语句第二步是将数据帧下载到CSV格式。

我想通过df_name下载所有的数据帧。代码:

def fun1():
import pandas as pd
d = {'col1': [1, 2], 'col2': [3, 4]}
d2 = {'col1': [-5, -6], 'col2': [-7, -8]}
df = pd.DataFrame(data=d)
df2 = pd.DataFrame(data=d2)
print('info', df.info())
print('info', df2.info())
return df, df2
def fun2(df):
from google.colab import files
name1 = 'positive.csv'
name2 = 'negative.csv'
df.to_csv(name1)
df2.to_csv(name2)
files.download(name1)
files.download(name2)

fun2(df) #looking something like this that download my df, func2 should read my df and df2 from fun1() 

我试着:

class tom:
def fun1(self):
import pandas as pd
d = {'col1': [1, 2], 'col2': [3, 4]}
d2 = {'col1': [-5, -6], 'col2': [-7, -8]}
df = pd.DataFrame(data=d)
df2 = pd.DataFrame(data=d2)
print('info', df.info())
print('info', df2.info())
self.df= df
self.df2 = df2

return df, df2

def fun2(self):
df,df2 = fun1()
from google.colab import files
name1 = 'positive.csv'
name2 = 'negative.csv'
df.to_csv(name1)
df2.to_csv(name2)
return files.download(name1) ,files.download(name2)

tom().fun2() #it download files but shows print of fun1 as well which I don't want. 

查找类似

的内容

tom().fun2(dataframe_name) #it just download the files nothing else

Answer 1

在类中直接设置永久变量如果它不改变

为动作定义乐趣。

class s:
import pandas as pd

d = {'col1': [1, 2], 'col2': [3, 4]}
d2 = {'col1': [-5, -6], 'col2': [-7, -8]}
df = pd.DataFrame(data=d)
df2 = pd.DataFrame(data=d2)

name1 = 'positive.csv'
name2 = 'negative.csv'
df.to_csv(name1)
df2.to_csv(name2)
def f():
print('info', df.info())
print('info', df2.info())

def fun(x):
from google.colab import files
return files.download(x)

运行

s.f() --it will print value only
s.fun(s.name1) --it will just download the file

Answer 2

也许你可以保存你需要的数据在一个类变量或创建另一个函数，保持数据从第一个函数你需要的值(让它叫a)，然后传递a给第二个函数作为参数。