如何从数组中获取权限名称值

Question

如果我的英语有点奇怪，我很抱歉，如果你不理解我的问题，请问我。所以，我想要这样的逻辑。当我尝试使用下面这样的简单数组时，它是有效的。

$a = array('car', 'bicycle', 'plane');
$b = array('car', 'boat', 'truck');
foreach ($a as $c)
{
if (in_array($c,$b))
{
echo "<b>" . $c . "</b>";
echo "rn";
} else
{
echo $c;
echo "rn";
}
}

但是，当我尝试将其应用于数组laravel-eloqunt时，看起来我无法从数组中获得值。我想匹配数据库中的数组(权限名称(。我想显示"权限"表中的所有权限名称，如果"权限名称"已应用于"角色"，我希望它显示为选中状态。这是我的代码：

$roles = Role::where('id', '=', 2)->with(['permissions'])->get();
$permissions = Permission::all();
foreach ($roles as $role)
{
foreach ($permissions as $permission)
{
$roleper = array($role['permissions']);
$pername = array($permissions);
if (in_array($pername,$roleper))
{
echo "<b>" . $permission['name'] . "</b>";
echo "rn";
} else {
echo $permission['name'];
echo "rn";
}
}
}

当我返回$roleper时，结果如下：

[[{"id":1,"name":"Add Color","guard_name":"web","created_at":"2020-08-10 02:49:25","updated_at":"2020-08-10 02:49:25","pivot":{"role_id":2,"permission_id":1}},{"id":2,"name":"Edit Color","guard_name":"web","created_at":"2020-08-10 02:50:49","updated_at":"2020-08-10 02:50:49","pivot":{"role_id":2,"permission_id":2}},{"id":3,"name":"Delete Color","guard_name":"web","created_at":"2020-08-10 02:50:57","updated_at":"2020-08-10 02:50:57","pivot":{"role_id":2,"permission_id":3}}]]

当我返回$pername时，结果是：

[[{"id":1,"name":"Add Color","guard_name":"web","created_at":"2020-08-10 02:49:25","updated_at":"2020-08-10 02:49:25"},{"id":2,"name":"Edit Color","guard_name":"web","created_at":"2020-08-10 02:50:49","updated_at":"2020-08-10 02:50:49"},{"id":3,"name":"Delete Color","guard_name":"web","created_at":"2020-08-10 02:50:57","updated_at":"2020-08-10 02:50:57"},{"id":4,"name":"Add Material","guard_name":"web","created_at":"2020-08-10 03:11:16","updated_at":"2020-08-10 03:11:16"},{"id":5,"name":"Edit Material","guard_name":"web","created_at":"2020-08-10 03:11:25","updated_at":"2020-08-10 03:11:25"},{"id":6,"name":"Delete Material","guard_name":"web","created_at":"2020-08-10 03:11:36","updated_at":"2020-08-10 03:11:36"},{"id":7,"name":"Add Brand","guard_name":"web","created_at":"2020-08-10 03:11:48","updated_at":"2020-08-10 03:11:48"},{"id":8,"name":"Edit Brand","guard_name":"web","created_at":"2020-08-10 03:11:54","updated_at":"2020-08-10 03:11:54"},{"id":9,"name":"Delete Brand","guard_name":"web","created_at":"2020-08-10 03:12:00","updated_at":"2020-08-10 03:12:00"},{"id":10,"name":"Add Product","guard_name":"web","created_at":"2020-08-10 03:12:09","updated_at":"2020-08-10 03:12:09"},{"id":11,"name":"Edit Product","guard_name":"web","created_at":"2020-08-10 03:12:17","updated_at":"2020-08-10 03:12:17"},{"id":12,"name":"Delete Product","guard_name":"web","created_at":"2020-08-10 03:12:23","updated_at":"2020-08-10 03:12:23"}]]

Answer 1

您可以使用内置方法array_incross、array_diff来获取两个数组之间的公共和不同元素

$permissions = Permission::all()->pluck('name')->toArray();
foreach ($roles as $role)
{
$rolePermissions = $role['permissions']->pluck('name')->toArray();
$maches = array_intersect($permissions, $rolePermissions);
$differences = array_diff($permissions, $rolePermissions);
//... loop $matches and $differences
}