在弹簧套中插入多行，用于一对多

Question

用户实体：

@Entity
public class User {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private int userId;
private String firstName;
private String lastName;
private String emailId;
private String phoneNumber;
@OneToMany(mappedBy="user", cascade= CascadeType.ALL, orphanRemoval = true)
private Set<Address> Addresses = new HashSet<Address>();

地址实体：

@Entity
public class Address {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private int addressId;
private String streetName;
private String houseNumber;
private String pinCode;
private String district;
private String state;
@ManyToOne(fetch = FetchType.LAZY, cascade= CascadeType.ALL)
@JoinColumn(name="userId")
@JsonIgnore
private User user = new User();

控制器类别：

@RestController
public class UserController {
@Autowired
IUserService iUserService; 
@RequestMapping(path = "/update")
public User updateCustomer(@RequestBody User user) {
return iUserService.save(user);
}
}

当我调用updateCustomer方法时，存储了错误的数据。插入的值如下所示，

SELECT * FROM ADDRESS ;
ADDRESS_ID      DISTRICT    HOUSE_NUMBER    PIN_CODE    STATE   STREET_NAME     USER_ID  
1   kalaburgi   287 585105  karnataka   jyanagar    2
2   bangalore   1387    560062  karnataka   anjanpura   3
(2 rows, 1 ms)

SELECT * FROM USER;
USER_ID     EMAIL_ID    FIRST_NAME      LAST_NAME   PHONE_NUMBER  
1   [e-mail]   sharan  gilke   9900669988
2   null    null    null    null
3   null    null    null    null

您能建议一下user表存储错误数据的原因吗。

来自邮递员的输入数据为：

{
"firstName" : "sharan",
"lastName" : "gilke",
"emailId" : "[e-mail]",
"phoneNumber" : "9900669988",
"addresses" : [{
"streetName" : "jyanagar",
"houseNumber" : "287",
"pinCode" : "585105",
"district" : "kalaburgi",
"state" : "karnataka"
},
{
"streetName" : "anjanpura",
"houseNumber" : "1387",
"pinCode" : "560062",
"district" : "bangalore",
"state" : "karnataka"
}
]
}

Answer 1

因为您为每个Address:创建了一个新的空User

private User user = new User();

这与JPA@OneToMany基本上是同一种错误：外键为空