我正在尝试分析Outlook中的电子邮件。我想要打印以下内容:
- 主题
- 正文(不包括发件人签名(
- 忽略转换中以前的所有电子邮件(回复和转发(
有什么方法可以在行与行之间的多个空格之前打印出正文(通常这就是签名与正文分离的方式(?
任何帮助都将不胜感激!
import win32com.client
#other libraries to be used in this script
import os
from datetime import datetime, timedelta
outlook = win32com.client.Dispatch('outlook.application')
mapi = outlook.GetNamespace("MAPI")
for account in mapi.Accounts:
print(account.DeliveryStore.DisplayName)
inbox = mapi.GetDefaultFolder(6)
messages = inbox.Items
messages.Sort('[ReceivedTime]', True)
received_dt = datetime.now() - timedelta(days=1)
received_dt = received_dt.strftime('%m/%d/%Y %H:%M %p')
messages = messages.Restrict("[ReceivedTime] >= '" + received_dt + "'")
messages = messages.Restrict("[SenderEmailAddress] = 'firstname.lastname@gmail.com'")
message = messages.GetFirst()
print ("Current date/time: "+ received_dt)
while message:
print(message.Subject)
print(message.body)
message = messages.GetNext ()
您可以使用正则表达式忽略三个换行符之后的所有内容(段落之间通常有一到两个换行符(:
import re
r = re.compile(r"(.*)nnn", re.MULTILINE + re.DOTALL)
# ...
while message:
# ...
match = r.match(message.body)
if match:
body_without_signature = r.match(message.body).groups(0)
else:
# No signature found
body_without_signature = message.body
print(body_without_signature)