当我只想打开列表中特定项目的表单时，为列表中的每个项目打开表单

Question

呈现按钮以显示表单的代码外观

import { useEffect, useState } from 'react';
import { useDispatch, useSelector } from 'react-redux';
import { deleteSong, getSongs, updateSong } from '../../store/song';
import ReactAudioPlayer from 'react-audio-player';
import { useHistory } from 'react-router';
import SongForm from '../AddSongForm';
import EditSongForm from '../EditSongForm';

const SongList = () => {
const [addShowForm, setAddShowForm] = useState(false);
const [editShowForm, setEditShowForm] = useState(false);
const history = useHistory()
const dispatch = useDispatch();
const songsObj = useSelector((state) => state.songState.entries);
const songs = Object.values(songsObj)
const user = useSelector((state) => state.session.user);
const CurrentUserId = user?.id
const remove = (e) => {
dispatch(deleteSong(e.target.id));
}
const addFormCheck = (e) => {
if (addShowForm) setAddShowForm(false)
if (!addShowForm) setAddShowForm(true)
}
const editFormCheck = (e) => {
if (editShowForm) setEditShowForm(false)
if (!editShowForm) setEditShowForm(true)
}
useEffect(() => {
dispatch(getSongs());
}, [dispatch]);

return (
<div>
<div>
<button onClick={addFormCheck}>add a song</button>
{addShowForm ?
<SongForm />
: null}
</div>
<h1>Song List</h1>
<ol>
{songs.map(({ id, songName, songLink, userId }) => (
<div className='songdetails' key={id}>
<p key={id}>songName={songName}</p>
<ReactAudioPlayer
src={songLink}
autoPlay
controls
key={songLink}
/>
{userId === CurrentUserId ?
<>
<div>
<button id={id} onClick={remove}>remove</button>
</div>
<div>
<button id={id} onClick={editFormCheck}>edit</button>
{editShowForm ?
<EditSongForm props={id} />
: null}
</div>
</>
: null}
</div>
))}
</ol>
</div>
);
};
export default SongList;

实际形式

import { useState } from "react";
import { useDispatch } from "react-redux";
import { updateSong } from "../../store/song";
import { useSelector } from "react-redux";
const EditSongForm = ({ props }) => {
console.log(props)
const dispatch = useDispatch();
const [songName, setSongName] = useState("");
const [songLink, setSongLink] = useState("");
const [errors, setErrors] = useState([]);

const reset = () => {
setSongName("");
setSongLink("");
// setAlbumName('');
// setArtistName('')
};
const user = useSelector((state) => state.session.user);
const userId = user?.id
const handleSubmit = async (e) => {
e.preventDefault();
const updatedSongDetails = {
id: props,
songName,
songLink,
userId
};
let updatedSong = await dispatch(updateSong(updatedSongDetails))
.catch(async (res) => {
const data = await res.json()
if (data && data.errors) setErrors(data.errors)
})
reset();
};
return (
<div className="inputBox">
<h1>Update A Song</h1>
<ul>
{errors.map((error, idx) => <li className='errors' key={idx}>{error}</li>)}
</ul>
<form onSubmit={handleSubmit}>
<input
type="text"
onChange={(e) => setSongName(e.target.value)}
value={songName}
placeholder="Song Name"
name="Song Name"
/>
<input
type="text"
onChange={(e) => setSongLink(e.target.value)}
value={songLink}
placeholder="Song Link"
name="Audio File"
/>
<button type="submit">Submit</button>
</form>
</div>
);
};
export default EditSongForm;

现在，当我有一个歌曲列表并单击编辑表单的按钮时，如果我上传了多首歌曲，它将适用于整个列表。我不知道如何使其足够具体，所以一次只能打开一个表单。

Answer 1

解决方案是为特定的歌曲细节创建一个组件，然后在.map.中渲染它

<h1>Song List</h1>
<ol>
{songs.map(({ id, songName, songLink, userId }) => (
<div>
<SpecificSong id={id} songName={songName} songLink={songLink} userId={userId} />
</div>
))}
</ol>