一旦玩家输入无效选项，不想让电脑播放他的回合.如何实现

Question

我是一个初学者，正在为"Rock Paper Scissors"；游戏我不想一遍又一遍地运行这个游戏(代码(，因此，使用while循环。现在，在"；否则："；当玩家键入任何无效的选择时，计算机也会播放该步骤；无效的选择。再次轮到你了"显示。

我想当玩家键入任何无效的选择时，计算机不应该播放它的回合，我们得到"；无效的选择。再次轮到你了"显示，保持游戏运行。

请检查我的代码并指出问题所在。请更正说明。提前感谢！

print("Welcome to the famous Rock Paper Scissors Game. n")
Choices = ["Rock", "Paper", "Scissors"]
while(True):
Player = input("Your turn: ")
Computer = random.choice(Choices)
print(f"Computer's turn: {Computer} n")

if Player == Computer:
print("That's a tie, try again! n")
elif Player == "Rock" and Computer == "Scissors":
print("You Won!!! n")
elif Player == "Rock" and Computer == "Paper":
print("Computer won! n")
elif Player == "Paper" and Computer == "Scissors":
print("Computer won! n")
elif Player == "Paper" and Computer == "Rock":
print("You Won!!! n")
elif Player == "Scissors" and Computer == "Paper":
print("You Won!!! n")
elif Player == "Scissors" and Computer == "Rock":
print("Computer won! n")
else:
print("Invalid choice. Play your turn again! n")

Answer 1

您可以在计算机播放之前检查输入是否有效，并使用continue-再次询问输入是否无效

Choices = ["Rock", "Paper", "Scissors"]
while(True):
Player = input("Your turn: ")
if Player not in Choices: # If it is not in Choices list above
print("Invalid choice. Play your turn again! n")
continue # This will re run the while loop again.

# If Player gives valid input, then continues this
Computer = random.choice(Choices)
print(f"Computer's turn: {Computer} n")
# The next lines ....

同时查看-中断、继续并通过