PHP或(||)运算符问题

Question

在PHP中面临有关or(双管(运算符的问题。

<?php


ini_set('display_errors', 1);
ini_set('display_startup_errors', 1);
error_reporting(E_ALL);
$token = fetchToken();
fetchActiveCompanies($token);
function fetchActiveCompanies($token){

//GET THE COMPANIES
$ch = curl_init();

$vars = 'Id, Member_Status__c, Name';
$query = 'https://xxx.my.salesforce.com/services/data/v50.0/query?q=SELECT ' . $vars . ' FROM Account';

$query = str_replace (' ', '%20', $query);
curl_setopt_array($ch, array(
CURLOPT_URL => $query,
CURLOPT_RETURNTRANSFER => true,
CURLOPT_ENCODING => "",
CURLOPT_MAXREDIRS => 10,
CURLOPT_TIMEOUT => 0,
CURLOPT_FOLLOWLOCATION => true,
CURLOPT_HTTP_VERSION => CURL_HTTP_VERSION_1_1,
CURLOPT_CUSTOMREQUEST => "GET",
CURLOPT_HTTPHEADER => array(
"Authorization: Bearer " . $token
),
));
$response = curl_exec($ch);
curl_close ($ch);

$obj = json_decode($response);
$records = $obj->records;

$activeRecords = array();
foreach($records as $record){

$id = $record->Id;
$status = $record->Member_Status__c;
var_dump($status);

if (($status == "Active") || ($status == "Pending Resignation")){
//if ($status == 'Active'){

$object = array();
$object['name'] = $record->Name;
$activeRecords[] = $object;

}
}

echo("record is " . json_encode($activeRecords));
return json_encode($activeRecords);
}
function fetchToken(){

//returns token string; 
}
?>

在foreach循环中的if语句行上获取Uncaught Error: Call to undefined function。用or和带括号和不带括号的病例进行试验。对于这两种比较来说，单if情况都很好，只是不适用于双管。我哪里错了？

编辑输出消息：

var dump: string(6) "Active" string(6) "Active" string(9) "Cancelled"
error: Fatal error: Uncaught Error: Call to undefined function  () [if line]

eror发生在$status var与字符串的比较中。在这种情况下，我只关心"活跃"one_answers"待辞职"状态。这就好像它在寻找一个else语句来覆盖"Cancelled"状态，因为它们应该是之后的第四个"Active"记录，并且它在第三次循环迭代时中断。

Answer 1

我能够重现这一点的唯一方法是使用U+2800而不是常规空格字符，这很傻，但你确定你没有使用无效的空格字符吗？

https://3v4l.org/eL3U8