将字符串中的所有大括号导出到数组中

Question

示例：

String = "(a(b[}7cv)))"

数组应该如下所示：["(","(","[","}",")",")",")"]

我的尝试：

if(s.charAt(i) == "(" ){
//add to array}

Answer 1

您可以简单地使用regex找到它们，并将它们添加到List 中

public static void main(String[] args) {
String foo = "(a(b[}7cv)))";
List<String> allMatches = new ArrayList<String>();
Matcher m = Pattern.compile("\W")
.matcher(foo);
while (m.find()) {
allMatches.add(m.group());
}
System.out.println(allMatches); 
}

如果它只是你想要的括号，你可能想把"[(){}\]\[]"作为Pattern.compile的正则表达式

Answer 2

如何获得非字母数字并添加到列表

String s = "(a(b[}7cv)))";
Pattern p = Pattern.compile("[^a-z0-9 ]", Pattern.CASE_INSENSITIVE);
Matcher m = p.matcher(s);
var list = new ArrayList<String>();
while (m.find()) {
list.add(String.valueOf(s.charAt(m.start())));
}
System.out.println(Arrays.toString(list.toArray()));

输出

[(, (, [, }, ), ), )]