Regex:匹配字符串，后跟句点/逗号，后跟空格

Question

我想打开我的text = "hello this is me, and only me. be carefull from 911. "

进入：text = "hello this is me,<break></break> and only me.<break></break> be carefull from 911. "

仅适用于后面跟着句点或逗号的字符串，而不是数字。

我试着用这个表达式：r"w+([.,])+s*"，但它也匹配数字。

Answer 1

您可以使用

re.sub(r'([^Wd_][.,])(s+)', r'1<break></break>2', text)

请参阅regex演示。

详细信息：

• ([^Wd_][.,])-组1(1(：任何字母，然后是.或,
• (s+)-组2(2(：一个或多个空白字符

请参阅Python演示：

import re
text = "hello this is me,<break></break> and only me.<break></break> be carefull from 911. "
print(re.sub(r'([^Wd_][.,])(s+)', r'1<break></break>2', text))
# => hello this is me,<break></break> and only me.<break></break> be carefull from 911.