如何解决此代码中的分段错误?

Question

我正在尝试制作一个中缀计算器，我目前正在尝试将字符数组中输入的数字转换为双精度。

这是我的代码：

#include <iostream>
#include<cmath>
using namespace std;
int main()
{
char exp[500];
const int SIZE = 100;
char temp[SIZE];
char op;
int strLen = 0, k, l, num = 0, fnum = 0;
double number = 0;
cin.getline(exp, 500,'n');
int i = 0, j = 0, fpoint=0;
cout << exp;
for (i = 0, j = 0; exp[j] != 0; i++)
{
if (i % 2 == 0)
{
for (int m = 0; exp[m] != ','; m++) //stopped working
temp[m] = exp[m];

cout << temp;

for (k = 0; k < SIZE && temp[k] != 0; k++)
{
strLen = k;
if (temp[k] == '.')
fpoint = k + 1;
}
cout << fpoint<<endl;

cout << "strLen" << strLen;
for (k = 0; k <= fpoint; k++)
{
num = num + ((temp[fpoint - k] - '0') * pow(10, k));
}
for (k = fpoint + 1, l = 0; k <= strLen; k++, l++)
{
fnum = fnum + ((temp[strLen - l] - '0') * pow(10, l));
}
number = num + (fnum / pow(10, strLen - fpoint + 1));
cout << number;
j = j + strLen + 1;
}
else
{
char op = temp[j];
cout << op;
}
}
system("pause");
return 0;
}

示例输入

2.5*3

它停止工作，并在标记位置上给出分割错误作为错误。

Answer 1

如果没有,字符，此行for (int m = 0; exp[m] != ','; m++) //stopped working将始终失败，因为exp[m] != ','将始终等于true，因此将超出触发"分段错误"的exp数组的末尾。