我是Django的新手，今天当我试图用数据库运行一个网站时，遇到了这个错误。我已经在StackOverflow和Django文档上搜索了所有的解决方案，但我无法修复它
这是一个与我相似的问题，但它不起作用。
我想创建一个链接，将用户从用户中的user.html移动到公民中的index.html
这是我的项目结构。很抱歉，因为我不能附上图片，所以我会尽量用最简单的方式解释。
[MYPROJECT]
->管理.py
->公民(文件夹(
-->模板(在这个文件夹中，我有citizen.html，index.html，layout.html(
-->管理员.py
-->型号.py
-->测试.py
-->urls.py
-->views.py
->myproject(文件夹(
-->设置.py
-->urls.py
-->等等我认为不重要的
->用户(文件夹(
-->模板(在这个文件夹中，我有login.html，user.html，layout.html(
-->urls.py
-->views.py
-->等等我认为不重要的
正如你所看到的，我在用户的模板文件夹中有user.html，在公民的模板文件夹内有index.html。
这是我的代码：
index.html公民内部
{% extends "citizens/layout.html" %}
{% block body %}
<h1>Hệ thống quản lý XNC</h1>
<table class="table">
<thead>
<tr>
<th scope="col">Số TT</th>
<th scope="col">Họ và tên công dân</th>
<th scope="col">Giới tính</th>
<th scope="col">Số Hộ chiếu</th>
<th scope="col">Chi tiết</th>
</tr>
</thead>
<tbody>
{% for citizen in citizens %}
<tr>
<th scope="row">{{ forloop.counter }}</th>
<td>{{ citizen.name }}</td>
<td>{{ citizen.sex }}</td>
<td>{{ citizen.sID }}</td>
<td><a href="{% url 'citizen' forloop.counter %}">Truy cập</a></td>
</tr>
{% endfor %}
</tbody>
</table>
{% endblock %}
user.html内部用户
{% extends "users/layout.html" %}
{% block body %}
<h1>Chào mừng, {{ request.user.username }}</h1>
<ul>
<li>Username: {{request.user.username }}</li>
</ul>
<a href="{% url 'citizen:citizens/' %}">Truy cập Cơ sở dữ liệu</a>
{% endblock %}
urls.py内部公民
from django.urls import path
from . import views
urlpatterns = [
path("", views.index, name="index"),
path("<int:citizen_id>", views.citizen, name="citizen"),
#path("<int:citizen_id>/passports", views.passport, name="passports")
]
views.py公民内部
from django.shortcuts import render
from django.http import HttpResponseBadRequest, HttpResponseRedirect, Http404
from django.urls import reverse
from .models import Citizen
# Create your views here.
def index(request):
return render(request, "citizens/index.html", {
"citizens": Citizen.objects.all()
})
def citizen(request, citizen_id):
try:
citizen = Citizen.objects.get(sID=citizen_id)
except Citizen.DoesNotExist:
raise Http404("Citizen not found")
return render(request, "citizens/citizen.html", {
"citizen": citizen,
})
urls.py在myproject中
"""htql2 URL Configuration
The `urlpatterns` list routes URLs to views. For more information please see:
https://docs.djangoproject.com/en/3.2/topics/http/urls/
Examples:
Function views
1. Add an import: from my_app import views
2. Add a URL to urlpatterns: path('', views.home, name='home')
Class-based views
1. Add an import: from other_app.views import Home
2. Add a URL to urlpatterns: path('', Home.as_view(), name='home')
Including another URLconf
1. Import the include() function: from django.urls import include, path
2. Add a URL to urlpatterns: path('blog/', include('blog.urls'))
"""
from django.contrib import admin
from django.urls import include, path
urlpatterns = [
path('admin/', admin.site.urls),
path('citizens/', include('citizens.urls')),
path('accounts/', include('django.contrib.auth.urls')),
path('users/', include('users.urls')),
]
urls.py内部用户
from django.urls import path
from . import views
urlpatterns = [
path("", views.index, name="index"),
path("login", views.login_view, name="login"),
path("logout", views.logout_view, name="logout"),
]
views.py内部用户
from django.views.decorators.csrf import csrf_exempt
from django.contrib.auth import authenticate, login, logout
from django.shortcuts import render
from django.http import HttpResponseBadRequest, HttpResponseRedirect, Http404
from django.urls import reverse
@csrf_exempt
# Create your views here.
def index(request):
if not request.user.is_authenticated:
return HttpResponseRedirect(reverse("login"))
return render(request, "users/user.html")
def login_view(request):
if request.method == "POST":
username = request.POST["username"]
password = request.POST["password"]
user = authenticate(request, username=username, password=password)
if user is not None:
login(request, user)
return HttpResponseRedirect(reverse("index"))
else:
return render(request, "users/login.html", {
"message": "Invalid credentials."
})
else:
return render(request, "users/login.html")
def logout_view(request):
pass
在user.html内部，我尝试过使用
<a href="{% url 'citizen:citizens/' %}">Go to Database</a>
但不起作用。
谢谢。我非常感激。
您已经尝试在此处使用{% url 'citizen:citizens/' %}，:之前的部分(citizen(是url名称空间，之后的部分(citizens(是url名。但是您没有使用任何名称空间，也没有citizens这样的url名称。
您可以通过指定app_name:在citizens.urls中添加命名空间
from django.urls import path
from . import views
app_name = 'citizens' # here
urlpatterns = [
path("", views.index, name="index"),
path("<int:citizen_id>", views.citizen, name="citizen"),
#path("<int:citizen_id>/passports", views.passport, name="passports")
]
接下来，您需要将url标记写为{% url 'citizens:index' %}:
<a href="{% url 'citizens:index' %}">Go to Database</a>