Roll no. |Sub1|sub2|
1. |20. |50. |
2. |80. |90. |
现在给出了样本数据,我需要找出受试者Sub1和Sub2之和超过100 的卷号
我尝试了这个,但没有运气
Select (sub1+sub2) as total
from table
where total > 100
您还必须在where条件中编写计算,因为where条件是在select语句之前处理的。
Select (sub1+sub2) as total
from table
where (sub1+sub2) > 100
使用CTE:可以使用别名,但不在查询范围内
CREATE TABLE tblName (roll_number INT, sub1 INT, sub2 INT);
INSERT INTO tblName (roll_number, sub1, sub2) VALUES (1 ,50, 20);
INSERT INTO tblName (roll_number, sub1, sub2) VALUES (2, 110, 20);
INSERT INTO tblName (roll_number, sub1, sub2) VALUES (3, 120, 20);
INSERT INTO tblName (roll_number, sub1, sub2) VALUES (4, 30, 20);
WITH cte AS (
SELECT roll_number AS RollNumber, (sub1 + sub2) AS Total
FROM tblName
)
SELECT * FROM cte
WHERE Total > 100
退货:
RollNumber | 总计 |
---|---|
2 | 130 |
3 | 140 |
您可以尝试这个简单的查询
WITH
CTE1 AS (SELECT SUM(`sub1`+`sub2`) AS subject_total,id as roll_num FROM `tbl` group by id )
SELECT * FROM CTE1
WHERE subject_total > 100;
演示链接