颤振加载json响应列表

Question

这个json响应在下面的列表中工作得很好。

[{"id"1","ename":"KING","sal":"5000">............

List<Emp> emp= (json.decode(response.body) as List)
        .map((data) => Emp.fromJson(data))
        .toList();

但是如何在列表加载数据时启动json停留项

{"items"[{"id" 1、"ename":"KING","sal": 5000 ............

Answer 1

用json.decode(response.body)['items']代替json.decode(response.body)

一个例子:

import 'dart:convert';
void main() {
  
  // sample body.response
  final j = '''{
  "items": [
  {"id":"1","ename":"KING","sal":"5000"},
  {"id":"2","ename":"KING","sal":"5000"}
  ]
  }''';
  List<Emp> emp = (json.decode(j)['items'] as List)
      .map((data) => Emp.fromJson(data))
      .toList();
  print(emp);
}
class Emp {
  String id;
  String ename;
  String sal;
  Emp({this.id, this.ename, this.sal});
  Emp.fromJson(Map<String, dynamic> json) {
    id = json['id'];
    ename = json['ename'];
    sal = json['sal'];
  }
  Map<String, dynamic> toJson() {
    final Map<String, dynamic> data = new Map<String, dynamic>();
    data['id'] = this.id;
    data['ename'] = this.ename;
    data['sal'] = this.sal;
    return data;
  }
}

Answer 2

List<Emp> emp= (json.decode(response.body)["items"] as List)
        .map((data) => Emp.fromJson(data))
        .toList();