如何在两层以上嵌套的对象数组上进行过滤

Question

我有一个嵌套的对象数组，我试图从其数组属性值的第三层使用属性来过滤给定的对象数组。例如，从下面的数组中，我喜欢使用属性"state" = "NY"过滤整个数组。

organisation = [
{
"dept_id":1,
"dept":{
"name":"finance",
"employees":[
{
"emp_id":1,
"name":"John",
"address":[
{
"country":"US",
"state":"NC"
}
]
}
]
}
},
{
"dept_id":2,
"dept":{
"name":"marketing",
"employees":[
{
"emp_id":2,
"name":"David",
"address":[
{
"country":"US",
"state":"NY"
}
]
}
]
}
},
{
"dept_id":3,
"dept":{
"name":"sales",
"employees":[
{
"emp_id":3,
"name":"Robert",
"address":[
{
"country":"US",
"state":"NC"
}
]
}
]
}
}
]

由于使用过滤器"state":"NY"，我的预期答案是

organisation = [
{
"dept_id":2,
"dept":{
"name":"marketing",
"employees":[
{
"emp_id":2,
"name":"David",
"address":[
{
"country":"US",
"state":"NY"
}
]
}
]
}
}
]

我如何使用javascript的过滤器方法来获得这个预期的结果。

Answer 1

您可以使用Array.prototype.filter,Array.prototype.some和Array.prototype.find函数来实现所需的结果。试试这个,

const organisation=[{dept_id:1,dept:{name:"finance",employees:[{emp_id:1,name:"John",address:[{country:"US",state:"NC"}]}]}},{dept_id:2,dept:{name:"marketing",employees:[{emp_id:2,name:"David",address:[{country:"US",state:"NY"}]}]}},{dept_id:3,dept:{name:"sales",employees:[{emp_id:3,name:"Robert",address:[{country:"US",state:"NC"}]}]}}];
const filter = "NY";
const res = organisation.filter(
item => item.dept.employees.some(
employee => employee.address.find(address => address.state === filter)
)
);
console.log(res);

在这里，我将filter应用于organization数组，然后检查employees数组中的任何员工是否具有state值">NY的address。"。

Answer 2

您可以使用Array.prototype.filter和Array.prototype.some的组合来过滤出您想要的结果。

const organisation=[{dept_id:1,dept:{name:"finance",employees:[{emp_id:1,name:"John",address:[{country:"US",state:"NC"}]}]}},{dept_id:2,dept:{name:"marketing",employees:[{emp_id:2,name:"David",address:[{country:"US",state:"NY"}]}]}},{dept_id:3,dept:{name:"sales",employees:[{emp_id:3,name:"Robert",address:[{country:"US",state:"NC"}]}]}}];

const result = organisation.filter(
item => item.dept.employees.some(
employee => employee.address.some(address => address.state === 'NY')  // Filter condition
)
);

console.log(result);

基本上，这过滤了organization数组，其中一些empoloyee有一些address,state值为'NY'。

Answer 3

const organisation=[{dept_id:1,dept:{name:"finance",employees:[{emp_id:1,name:"John",address:[{country:"US",state:"NC"}]}]}},{dept_id:2,dept:{name:"marketing",employees:[{emp_id:2,name:"David",address:[{country:"US",state:"NY"}]}]}},{dept_id:3,dept:{name:"sales",employees:[{emp_id:3,name:"Robert",address:[{country:"US",state:"NC"}]}]}}];
const filter = "NY";
const res = organisation.filter(item => item.dept.employees.find(add => JSON.stringify(add.address).includes('"state":"' + filter + '"')));
console.log(res);

Answer 4

你只可以使用过滤器

filtered = organisation.filter(el => el.dept.employees.filter(el => el.address.filter(el => el.state == 'NY').length > 0 ).length > 0);

organisation = [
{
"dept_id":1,
"dept":{
"name":"finance",
"employees":[
{
"emp_id":1,
"name":"John",
"address":[
{
"country":"US",
"state":"NC"
}
]
}
]
}
},
{
"dept_id":2,
"dept":{
"name":"marketing",
"employees":[
{
"emp_id":2,
"name":"David",
"address":[
{
"country":"US",
"state":"NY"
}
]
}
]
}
},
{
"dept_id":3,
"dept":{
"name":"sales",
"employees":[
{
"emp_id":3,
"name":"Robert",
"address":[
{
"country":"US",
"state":"NC"
}
]
}
]
}
}
]

filtered = organisation.filter(el => el.dept.employees.filter(el => el.address.filter(el => el.state == 'NY').length > 0 ).length > 0);
console.log(filtered);

Answer 5

我这样过滤它。试试这个

const filteredOrg = [];

organisation.forEach((item) => {
item.dept.employees.forEach((employe) => {
employe.address.forEach((address) => {
if (address.state === "NY") {
filteredOrg.push(item);
}
});
});
});

我希望它对你也有用。

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