删除列表中重复的字符串

Question

如何编写一个删除任何重复字符串的函数?在列表dates中，字符串'2017-11-01 00:00:00','2018-12-01 00:00:00'被重复了两次或两次以上。我想让它达到Expected Output的位置，并且每个字符串只有1个大小写。

dates = ['2017-09-01 00:00:00', '2017-10-01 00:00:00', '2017-11-01 00:00:00', '2017-11-01 00:00:00', '2017-11-01 00:00:00', '2017-12-01 00:00:00', '2018-01-01 00:00:00', '2018-02-01 00:00:00', '2018-03-01 00:00:00', '2018-04-01 00:00:00', '2018-05-01 00:00:00', '2018-06-01 00:00:00', '2018-07-01 00:00:00', '2018-08-01 00:00:00', '2018-09-01 00:00:00', '2018-10-01 00:00:00', '2018-11-01 00:00:00', '2018-12-01 00:00:00', '2018-12-01 00:00:00', '2019-01-01 00:00:00']

预期输出:

['2017-09-01 00:00:00', '2017-10-01 00:00:00', '2017-11-01 00:00:00', '2017-12-01 00:00:00', '2018-01-01 00:00:00', '2018-02-01 00:00:00', '2018-03-01 00:00:00', '2018-04-01 00:00:00', '2018-05-01 00:00:00', '2018-06-01 00:00:00', '2018-07-01 00:00:00', '2018-08-01 00:00:00', '2018-09-01 00:00:00', '2018-10-01 00:00:00', '2018-11-01 00:00:00', '2018-12-01 00:00:00', '2019-01-01 00:00:00']

Answer 1

假设您想要过滤掉连续重复时，可以使用列表推导式:

[dates[0]]+[dates[i] for i in range(1, len(dates)) if dates[i-1]!=dates[i]]

或itertools.groupby:

from itertools import groupby
[list(g)[0] for i,g in groupby(dates)]

输出:

['2017-09-01 00:00:00', '2017-10-01 00:00:00', '2017-11-01 00:00:00',
'2017-12-01 00:00:00', '2018-01-01 00:00:00', '2018-02-01 00:00:00',
'2018-03-01 00:00:00', '2018-04-01 00:00:00', '2018-05-01 00:00:00',
'2018-06-01 00:00:00', '2018-07-01 00:00:00', '2018-08-01 00:00:00',
'2018-09-01 00:00:00', '2018-10-01 00:00:00', '2018-11-01 00:00:00',
'2018-12-01 00:00:00', '2019-01-01 00:00:00']