语法错误:JSON.parse:JSON数据的第1行第2列出现意外字符

Question

我在JSON.parse 上遇到语法错误

const userInfo =
localStorage.getItem("user") !== "undefined"
? JSON.parse(localStorage.getItem("user"))
: localStorage.clear();

我在登录组件中首先设置了用户：

const responseGoogle = (response) => {
const decoded = jwt_decode(response.credential);
const anyUser =localStorage.setItem("user", decoded);

这是我的JSON内容：

aud: "57**********-jc601taprt3p68jkkv6pig3ntqk19nt2.apps.googleusercontent.com"
​
azp: "57**********-jc601taprt3p68jkkv6pig3ntqk19nt2.apps.googleusercontent.com"
​
email: "[e-mail]"
​
email_verified: true
​
exp: 16676*****
​
family_name: "John"
​
given_name: "Doe"
​
iat: 16676*****
​
iss: "https://accounts.google.com"
​
jti: "dbd78b14d4f87f1e32b0ecfc2f8076**********"
​
name: "John Doe"
​
nbf: 16676*****
​
picture: "https://lh3.googleusercontent.com/a/ALm5wu1A2dnuB2PU3zd6Pcc52GGdTWw*****IcMahE_XXw=s96-c"
​
sub: "1167323005026********"

我使用了jwt_decode，Login组件有setItem，而我的Home组件有getItem

Answer 1

编辑：根据问题更新进行更新。发布的json无效。键需要被引用，值需要逗号——它需要看起来像下面这样：

{
"aud": "57**********-jc601taprt3p68jkkv6pig3ntqk19nt2.apps.googleusercontent.com",
"azp": "57**********-jc601taprt3p68jkkv6pig3ntqk19nt2.apps.googleusercontent.com",
"email": "[e-mail]",
"email_verified": true,
"exp": 1667600000,
"family_name": "John",
"given_name": "Doe",
"iat": 1667600000,
"iss": "https://accounts.google.com",
"jti": "dbd78b14d4f87f1e32b0ecfc2f8076**********",
"name": "John Doe",
"nbf": 166760000,
"picture": "https://lh3.googleusercontent.com/a/ALm5wu1A2dnuB2PU3zd6Pcc52GGdTW,w*****IcMahE_XXw=s96-c",
"sub": 11673230050260000
}

这是一个很好的资源来帮助json——它可能有点棘手，但一旦你把它放下，它就会变得更有意义。https://www.w3schools.com/js/js_json_datatypes.asp

尝试使用此工具调整jsonhttps://jsonformatter.org/json-parser