如何在没有缓冲的情况下读取子流程管道

Question

如何在不等待的情况下读取管道的缓冲区。子进程正在执行Swift脚本。如果它是一个python脚本，那么有一个python的标志使管道不缓冲(-u(。有其他解决方法吗？

sub_proc = subprocess.Popen(['swift', 'script2.swift'], stdout=subprocess.PIPE, stderr=subprocess.PIPE)
thr1 = threading.Thread(target=self.pipe_reader, args=[sub_proc.stdout]).start()
thr2 = threading.Thread(target=self.pipe_reader, args=[sub_proc.stderr]).start()

def pipe_reader(self, pipe):
for line in iter(pipe.readline, b''):
self.q.put((pipe, line))
self.q.put((pipe, None))

Answer 1

我解决了它。更改了行(添加stdbuf-o0作为参数(

sub_proc = subprocess.Popen(['swift', 'script2.swift'], stdout=subprocess.PIPE, stderr=subprocess.PIPE)

至

sub_proc = subprocess.Popen(['stdbuf', '-o0','swift', 'script2.swift'], stdout=subprocess.PIPE, stderr=subprocess.STDOUT)

有关stdbuf的更多信息：https://www.gnu.org/software/coreutils/manual/html_node/stdbuf-invocation.html