使用以下代码进行API调用:
req = urllib.request.Request(url, body, headers)
try:
response = urllib.request.urlopen(req)
string = response.read().decode('utf-8')
json_obj = json.loads(string)
返回以下内容:
{"forecast": [17.588294043898163, 17.412641963452206],
"index": [
{"SaleDate": 1629417600000, "Type": "Type 1"},
{"SaleDate": 1629504000000, "Type": "Type 2"}
]
}
如何将此api响应转换为Panda DataFrame以将pandas DataFrame
中的字典转换为以下格式Forecast SaleDate Type
17.588294043898163 2021-08-16 Type 1
17.412641963452206 2021-08-17 Type 1
您可以使用以下命令。它使用pandas.Series
将字典转换为列,使用pandas.to_datetime
从毫秒时间戳映射正确的日期:
d = {"forecast": [17.588294043898163, 17.412641963452206],
"index": [
{"SaleDate": 1629417600000, "Type": "Type 1"},
{"SaleDate": 1629504000000, "Type": "Type 2"}
]
}
df = pd.DataFrame(d)
df = pd.concat([df['forecast'], df['index'].apply(pd.Series)], axis=1)
df['SaleDate'] = pd.to_datetime(df['SaleDate'], unit='ms')
输出:
forecast SaleDate Type
0 17.588294 2021-08-20 Type 1
1 17.412642 2021-08-21 Type 2
这里有一个解决方案,你可以尝试一下,使用list comprehension
来平化数据。
import pandas as pd
flatten = [
{"forecast": j, **resp['index'][i]} for i, j in enumerate(resp['forecast'])
]
pd.DataFrame(flatten)
forecast SaleDate Type
0 17.588294 1629417600000 Type 1
1 17.412642 1629504000000 Type 2