无法在 Python 中正确合并列表 - 最后一个元素未合并

Question

有两个列表:

MAIN: ['Lists ', 'nThe first list', 'n 4. Empty', 'n 5. Orange', 'n 6. Lemon', 'n 7. 2 Tangerines']
FOR REPLACEMENT: ['The second list is', 'n3. Apple ', 'n4. Banana ', 'n5. Pear', 'n8. Milk']

如何在这段代码中编写一个条件，使第8个元素不丢失?

a = ['Lists', 'The first list', '4. Empty', '5. Empty', '6. Lemon', '7. 2 Tangerines']
b = ['The second list is', '3. Apple ', '4. Banana ', '5. Pear', '8. Other']
w = []
for i in range(len(a)):    # find all the unnumbered elements of the first list, add them to the final one in order
if a[i][0] not in ['1', '2', '3', '4', '5', '6', '7', '8', '9']:
w.append('0. ' + a[i])
else:
n = i
break
for i in range(len(b)):     # find all the unnumbered elements of the second list, also add them to the final one in order
if b[i][0] not in ['1', '2', '3', '4', '5', '6', '7', '8', '9']:
w.append('0. ' + b[i])
else:
m = i
break
w += a[n:]      # adding the numbered elements of the first list
for i in range(m, len(b)):      # we check the numbered elements of the second list, do the necessary action(replace/add)
for j in range(len(w)):
if b[i][:b[i].index('.')] == w[j][:w[j].index('.')]:
w[j] = b[i]
break
elif int(b[i][:b[i].index('.')]) < int(w[j][:w[j].index('.')]):
w = w[:j] + [b[i]] + w[j:]
break
k = 0       # beautiful output
while w[k][0] == '0':
w[k] = w[k][3:]
k += 1
print('n'.join(w))

必须将第一个列表中的元素替换为第二个列表中的元素。

在第一个列表中，数字总是按顺序排列。在第二种情况下，这可能不是。如果第二个列表中有一个数字不在主列表中，那么它应该分别插入到顶部或底部。

我不能输出元素8。9. 10. 等等......简单地说，末尾的元素不会被插入到主列表中。预期结果:

Lists
The first list
The second list is
3. Apple
4. Banana
5. Pear
6. Lemon
7. 2 Tangerines
8. Other

Answer 1

试试这个:

a = ['Lists', 'The first list', '4. Empty', '5. Empty', '6. Lemon', '7. 2 Tangerines']
b = ['The second list is', '3. Apple ', '4. Banana ', '5. Pear', '8. Other']
x = sorted([
x for x in a+b
if x[0].isdigit() and x[3:] != 'Empty'
], key=lambda x: int(x[0]))
for x in x: print(x)