这里有两组数据:
data_feb = ['1st February', 45, 68, 70, 61, 54, 80, 72, 69, 73, 72, 58, 72, 64, 45, 42]
data_aug = ['1st August', 19, 27, 41, 42, 9, 14, 29, 34, 25, 29, 44, 43, 6, 17]
在这里循环创建另一个列表:
for i in data_feb:
#
if type(i) == int:
feb_numbers.append(i)
for i in data_aug:
if type(i) == int:
aug_numbers.append(i)
但这里我有一个算法来排序它们:
feb_zero_to_ten = []
feb_ten_to_twenty = []
feb_twenty_to_thirty = []
feb_thirty_to_forty = []
feb_forty_to_fifty = []
feb_fifty_to_sixty = []
feb_sixty_to_seventy = []
feb_seventy_to_eighty = []
feb_eighty_to_ninety = []
feb_ninety_to_hundred = []
aug_zero_to_ten = []
aug_ten_to_twenty = []
aug_twenty_to_thirty = []
aug_thirty_to_forty = []
aug_forty_to_fifty = []
aug_fifty_to_sixty = []
aug_sixty_to_seventy = []
aug_seventy_to_eighty = []
aug_eighty_to_ninety = []
aug_ninety_to_hundred = []
# for loop to iterate over months numbers, sorting them into their correct columns by the 'tens' digit
for i, j in zip(feb_numbers, aug_numbers):
if 0 <= i < 10 and 0 <= j < 10:
feb_zero_to_ten.append(i)
aug_zero_to_ten.append(j)
elif 10 <= i < 20 and 10 <= j < 20:
feb_ten_to_twenty.append(i)
aug_ten_to_twenty.append(j)
elif 20 <= i < 30 and 20 <= j < 30:
feb_twenty_to_thirty.append(i)
aug_twenty_to_thirty.append(j)
elif 30 <= i < 40 and 30 <= j < 40:
feb_thirty_to_forty.append(i)
aug_thirty_to_forty.append(j)
elif 40 <= i < 50 and 40 <= j < 50:
feb_forty_to_fifty.append(i)
aug_forty_to_fifty.append(j)
elif 50 <= i < 60 and 50 <= j < 60:
feb_fifty_to_sixty.append(i)
aug_fifty_to_sixty.append(j)
elif 60 <= i < 70 and 60 <= j < 70:
feb_sixty_to_seventy.append(i)
aug_sixty_to_seventy.append(j)
elif 70 <= i < 80 and 70 <= j < 80:
feb_seventy_to_eighty.append(i)
aug_seventy_to_eighty.append(j)
elif 80 <= i < 90 and 80 <= j < 90:
feb_eighty_to_ninety.append(i)
aug_eighty_to_ninety.append(j)
elif 90 <= i < 100 and 90 <= j < 100:
feb_ninety_to_hundred.append(i)
aug_ninety_to_hundred.append(j)
使用zip()的方法不起作用。我想知道如果使用这种方法是不值得的，我也试图使这段代码尽可能高效，所以任何指针将是非常有帮助的。谢谢你。
data_feb = ['1st February', 45, 68, 70, 61, 54, 80, 72, 69, 73, 72, 58, 72, 64, 45, 42]
data_aug = ['1st August', 19, 27, 41, 42, 9, 14, 29, 34, 25, 29, 44, 43, 6, 17]
feb_numbers=[i for i in data_feb if isinstance(i,int) ]
aug_numbers=[i for i in data_aug if isinstance(i,int) ]
from itertools import groupby
[list(g) for k,g in groupby(sorted(aug_numbers),key=lambda x :x//10)]
输出:
[[6, 9], [14, 17, 19], [25, 27, 29, 29], [34], [41, 42, 43, 44]]
您可以使用itertools groupby对这些数字进行分组
你的方法有缺陷。你测试i和j都在一个范围内，但如果你看看你的数字，你会发现这可能不会发生，像(45, 19)这样的东西不适合任何if。如果你看一下你想要实现的逻辑，那么你会注意到你实际上想要用它们的前导数字(十位)分开你的数字，一个简单的方法是制作桶并像这样填充它们:
feb_buckets = [[] for item in range(10)] # this makes a list of 10 buckets (lists)
aug_buckets = [[] for item in range(10)]
for feb, aug in zip(feb_numbers,aug_numbers):
feb_bucket[feb//10].append(feb) # // is integer division (which rounds down)
aug_bucket[aug//10].append(aug)
一旦你理解了逻辑，你就可以通过使用@ajay方法和使用itertools.groupby
进一步简化代码- 不要手工创建所有列表，只需创建列表的列表，然后通过索引访问它们。
- 对于
0~10范围内的数字，使用feb[0]~10~20~feb[1]等。 - 如果你不知道列表是否有相同的长度，使用
find_in_range函数为每个列表。
您可以使用下面的代码:
data_feb = ['1st February', 45, 68, 70, 61, 54, 80, 72, 69, 73, 72, 58, 72, 64, 45, 42]
data_aug = ['1st August', 19, 27, 41, 42, 9, 14, 29, 34, 25, 29, 44, 43, 6, 17]
#Dont create all list by hand, just create list of lists and then acces them by index
feb = [[] for i in range(10)]
aug = [[] for i in range(10)]
def find_in_range(in_list, out_list):
for x in sorted(in_list[1:]): #exclude the first index, because it is a string
for i in range(10):
if i*10 < x < (i+1)*10:
out_list[i].append(x)
find_in_range(data_feb, feb)
find_in_range(data_aug, aug)
print("Feb: ", feb)
print("Aug", aug)
输出:
Feb: [[], [], [], [], [42, 45, 45], [54, 58], [61, 64, 68, 69], [72, 72, 72, 73], [], []]
Aug [[6, 9], [14, 17, 19], [25, 27, 29, 29], [34], [41, 42, 43, 44], [], [], [], [], []]
可以看到feb列表的前四个数组是空的，因为data_feb列表中没有0-40之间的数字。
完成排序的一个好方法是拥有一个排序列表的列表。最终的输出将是fed_sorted和aug_sorted。i-th列表将在[i*10, (i+1)*10)的范围内。
data_feb = ['1st February', 45, 68, 70, 61, 54, 80, 72, 69, 73, 72, 58, 72, 64, 45, 42]
data_aug = ['1st August', 19, 27, 41, 42, 9, 14, 29, 34, 25, 29, 44, 43, 6, 17]
feb_numbers = [x for x in data_feb if type(x) == int]
aug_numbers = [x for x in data_aug if type(x) == int]
GROUP_SIZE = 10 # 0-9, 10-19, 20-29....
feb_sorted = [[x for x in feb_numbers if x in range(i * 10, (i + 1) * 10)] for i in range(GROUP_SIZE)]
aug_sorted = [[x for x in aug_numbers if x in range(i * 10, (i + 1) * 10)] for i in range(GROUP_SIZE)]
print(feb_sorted)
print(aug_sorted)
你的代码的第一部分可以变得更有效率，像这样:
data_feb = ['1st February', 45, 68, 70, 61, 54, 80, 72, 69, 73, 72, 58, 72, 64, 45, 42]
data_aug = ['1st August', 19, 27, 41, 42, 9, 14, 29, 34, 25, 29, 44, 43, 6, 17]
data_feb = [x for x in data_feb if x == int]
data_aug = [x for x in data_aug if x == int]
对于第二部分，你不清楚你想要实现什么。你能多给我一些背景资料吗?你为什么需要这么多清单?排序是什么意思?为什么需要这样排序?