获取测试号如果上面一行包含特定文本

Question

我有一个junit文件。如何从testt获得号码?

如果上面一行包含"/system- error "或"/failure"然后测试失败，写入失败id为test的文件。

如果上面一行包含"/system-out"则测试成功，写入通过的文件id test。

例子"/system-err"

<system-err>Assertion Failure at Navigation.swift:88:Failed to get matching snapshot: No matches found for first query match sequence: `Descendants matching type NavigationBar`, given input App element pid: 21141 (no attribute values faulted in)</system-err>
<system-out>testIT: C477997</system-out>

例子"/failure"

>      <failure message='Assertion Failure at Element.swift:277:Failed to get matching snapshot: No matches found for Elements matching
> predicate &apos;&quot;One&quot; IN identifiers&apos; from input {(
>         Button, identifier: &apos;dictation&apos;, label: &apos;Диктовать&apos;, Disabled,
>         Button, label: &apos;Почему мне не приходит СМС?&apos;,
>         Button, label: &apos;Назад&apos;,
>         Button,
>         Button, label: &apos;Продолжить&apos;
>     )}'>
>         </failure>
>         <system-out>testIT: C478067</system-out>

通过了测试

<system-out>      Setting up automation session</system-out>
<system-out>testIT: C478057</system-out>

失败文件包含id

477997
478067

传递的文件包含id

478057

我试着

xmllint  $1 | awk -F'testIT: C|, | \(' '/testIT:/{print $2"n"$4"n"$6}'| awk 'NF!=0' | sort| uniq|  2>/dev/null > successfullCases.xml

但是我得到

470836</system-out>
477975</system-out>
477997</system-out>
478057</system-out>
478067</system-out>
478098</system-out>

完整文件https://disk.yandex.ru/d/DhdlvwfYj4J00A

Answer 1

让我们试试:

arr=(`grep -En "C[0-9]{6}" $1 | cut -d":" -f 1 | xargs`)

>fail.out
>err.out
>pass.out
for i in ${!arr[@]}; do
line_num="${arr[$i]}"
if head -$line_num $1 | tail -2 | grep -q "/system-err"
then
echo -ne "$i) Line: $line_numttErrorttID: "
head -$line_num $1 | tail -1 | grep -Eo '[0-9]{6}'
head -$line_num $1 | tail -1 | grep -Eo '[0-9]{6}' >> err.out
#--------------------------------------------------------
elif head -$line_num $1 | tail -2 | grep -q "/failure"
then
echo -ne "$i) Line: $line_numttFailurettID: "
head -$line_num $1 | tail -1 | grep -Eo '[0-9]{6}'
head -$line_num $1 | tail -1 | grep -Eo '[0-9]{6}' >> fail.out
# ----------------------------------------------------------
elif head -$line_num $1 | tail -2 | grep -q "/system-out"
then
echo -ne "$i) Line: $line_numttPassttID: "
head -$line_num $1 | tail -1 | grep -Eo '[0-9]{6}'
head -$line_num $1 | tail -1 | grep -Eo '[0-9]{6}' >> pass.out
# ----------------------------------------------------------
fi
done

将脚本保存在一个文件中，并尝试这样运行:

[user@host]# bash script.sh report.junit

Answer 2

试试这个:

grep -Eo '[0-9]{6}' file.txt

描述:

-E或--extended-regexp:将模式解释为扩展正则表达式

和

-o或--only-matching:只打印匹配行中匹配(非空)的部分，每个部分在单独的输出行上。

更多阅读:

1. grep(1):打印行匹配模式- Linux手册页

注意:

同样，如果您想导出"error";pass"或者"失败"，您应该编写一个脚本逐行处理您的输入文件。我可以帮你更多的忙。

Answer 3

假设您的输入类似于:

$ cat input_file
<system-err>Assertion Failure at Navigation.swift:88:Failed to get matching snapshot: No matches found for first query match sequence: `Descendants matching type NavigationBar`, given input App element pid: 21141 (no attribute values faulted in)</system-err>
<system-out>testIT: C477997</system-out>
>      <failure message='Assertion Failure at Element.swift:277:Failed to get matching snapshot: No matches found for Elements matching
> predicate &apos;&quot;One&quot; IN identifiers&apos; from input {(
>         Button, identifier: &apos;dictation&apos;, label: &apos;Диктовать&apos;, Disabled,
>         Button, label: &apos;Почему мне не приходит СМС?&apos;,
>         Button, label: &apos;Назад&apos;,
>         Button,
>         Button, label: &apos;Продолжить&apos;
>     )}'>
>         </failure>
>         <system-out>testIT: C478067</system-out>
<system-out>      Setting up automation session</system-out>
<system-out>testIT: C478057</system-out>

使用sed

$ cat script.sed
N
s~.*/(system-err|failure).*n.*testIT[^0-9]*([0-9]+).*~2~pwfail.txt
s~.*/system-out.*n.*testIT[^0-9]*([0-9]+).*~1~pwpass.txt
p

您可以使用以下脚本:

$ sed -Enf script.sed input_file

或者作为一行

$ sed -Ene 'N;{s~.*/(system-err|failure).*n.*testIT[^0-9]*([0-9]+).*~2~pwfail.txt' -e 's~.*/system-out.*n.*testIT[^0-9]*([0-9]+).*~1~pwpass.txt' -e '}' input_file

$ head {pass,fail}.txt
==> pass.txt <==
478057
==> fail.txt <==
477997
478067