使用Python将CSV文件转换为多个字典



我想将CSV文件转换为字典列表。例如,我有一个CSV文件,其数据顺序如下:

名称、爱好、年龄

萨米足球6

安吉拉象棋12

,输出应该像这样:

(

{"name": "Sammy", "hobby": "football", "age": "6"},
{"name": "Angela", "hobby": "chess", "age": "12"}

)你有什么建议吗?

如果您可以使用Pandas,则可以使用-

import pandas as pd
df = pd.read_csv('/path/to/csv/file')
records = df.to_dict(orient='records')

输出应该像-

[
{"name": "Sammy", "hobby": "football", "age": "6"},
{"name": "Angela", "hobby": "chess", "age": "12"}
]

这里,我们将csv文件读取为pandas DataFrame,然后将dataframe转换为dict。如果pandas不可用,请使用

安装
pip install pandas

您可以将此代码仅用于csv模块:

import csv
with open(filename, mode='r') as infile:
reader = csv.reader(infile, skipinitialspace=True)
keys = next(reader)
ret_list = []
for row in reader:
ret_list.append({})
for key, value in zip(keys, row):
ret_list[-1][key] = value

更新:这是一个更实用的解决方案:

import csv
with open(filename, mode='r') as infile:
reader = csv.DictReader(infile, skipinitialspace=True)
d = [r for r in reader]

这是一个创建字典列表的方法;

import pandas as pd
# Replace './a.xlsx' with path to your file
# In case file is in csv use pd.read_csv instead
df = pd.read_excel('./a.xlsx')
# Create an empty list to hold the list of dictionaries
list_of_dicts = list()
# Use iterrows to iterate over all rows
for index, row in df.iterrows():
# Empty dictionary to be used as tmp value for each dict in list
dict_person = {}
# Iterate over each column on the row, update the dictionary key and value
for col in range(len(row.index)):
dict_person.update({str(row.index[col]) : row[col]})
# Add the temporary dict to the list
list_of_dicts.append(dict_person)

将产生结果;

[{'name': 'Sammy', 'hobby': 'football', 'age': 6},
{'name': 'Angela', 'hobby': 'chess', 'age': 12}]

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