如何将每个字典的键之和附加到另一个键上?

Question

我有一个json格式如下:-

l = {'itc': 'ball','classes': [{'scores': [{'len': 89,'width':50},{'len': 27,'width': 17}]},
{'scores': [{'len': 90,'width': 44},{'len': 0,'width': 0}]},
{'scores': [{'len': 50,'width': 26},{'len': 0,'width': 0}]}]}

现在我想创建一个新的字典列表。如以下:-

output= [{'result': [{'len': 89, 'width': 50}, {'len': 27, 'width': 17}], 'total': 116}, {'result': [{'len': 90, 'width': 44}, {'len': 0, 'width': 0}], 'total': 90}, {'result': [{'len': 50, 'width': 26}, {'len': 0, 'width': 0}], 'total': 50}]

我能够划分值并能够以所需的格式放置，但我无法将每个字典的总分键'len'附加到每个字典结果的total中。它在计算所有字典的值。我得到的代码和输出如下:-

added=[]
output=[]
for k,v in l.items():
if k=='classes':
for i in v:
for ke,ve in i.items():
if ke=='scores':
for j in ve:
for key,val in j.items():
if key=='len':
add = val
added.append(add)
sumed=sum(added)
out={'result':ve,'total':sumed}
output.append(out)
print(output)

输出结果:-

[{'result': [{'len': 89, 'width': 50}, {'len': 27, 'width': 17}], 'total': 116}, {'result': [{'len': 90, 'width': 44}, {'len': 0, 'width': 0}], 'total': 206}, {'result': [{'len': 50, 'width': 26}, {'len': 0, 'width': 0}], 'total': 256}]   

正如您所看到的，它将所有值相加并将它们附加到键total。如何将每个字典score的和附加到每个字典result的total键上，如下所示?

output= [{'result': [{'len': 89, 'width': 50}, {'len': 27, 'width': 17}], 'total': 116}, {'result': [{'len': 90, 'width': 44}, {'len': 0, 'width': 0}], 'total': 90}, {'result': [{'len': 50, 'width': 26}, {'len': 0, 'width': 0}], 'total': 50}]

Answer 1

使用sum获取总数:

res = [{"result" : cl["scores"], "total" :  sum(d["len"] for d in cl["scores"])} for cl in l["classes"]]
print(res)

[{'result': [{'len': 89, 'width': 50}, {'len': 27, 'width': 17}], 'total': 116}, {'result': [{'len': 90, 'width': 44}, {'len': 0, 'width': 0}], 'total': 90}, {'result': [{'len': 50, 'width': 26}, {'len': 0, 'width': 0}], 'total': 50}]

或等价的for-loop:

res = []
for cl in l["classes"]:
scores = cl["scores"]
total = sum(d["len"] for d in cl["scores"])
res.append({"result": scores, "total": total})