单个字典，包含相同键下的多个列表的列表.希望将同一键下的所有值组合成单个列表

Question

我有一个字典，在一个键-下包含多个列表下面是我的字典的输出示例:

print(dic)

输出:

{1: [[1, 2, 3, 4, 5, 6, 7],
[5, 1, 4, 34, 3, 65, 0, 2],
[2, 5, 4, 5, 7, 8, 4, 7]],
2: [[1, 5, 4, 5, 0, 1, 4, 6],
[2, 2, 3, 5, 6, 6, 3, 9]],
3: [[12, 35, 42, 53, 70, 71, 74, 76],
[6, 11, 16, 17, 38, 62, 66, 77]]}

我希望为每个键下的所有列表创建一个列表。因此，我正在寻找的输出示例看起来像这样:

{1: [[1, 2, 3, 4, 5, 6, 7, 5, 1, 4, 34, 3, 65, 0, 2, 2, 5, 4, 5, 7, 8, 4, 7]],
2: [[1, 5, 4, 5, 0, 1, 4, 6, 2, 2, 3, 5, 6, 6, 3, 9]],
3: [[12, 35, 42, 53, 70, 71, 74, 76, 6, 11, 16, 17, 38, 62, 66, 77]]}

我尝试了一个字典理解，几乎没有成功，以及一个for循环，我迭代了dic.items()。

Answer 1

可以使用字典推导式:

{key: [[item for sublist in value for item in sublist]] for key, value in data.items()}

这个输出:

{
1: [[1, 2, 3, 4, 5, 6, 7, 5, 1, 4, 34, 3, 65, 0, 2, 2, 5, 4, 5, 7, 8, 4, 7]],
2: [[1, 5, 4, 5, 0, 1, 4, 6, 2, 2, 3, 5, 6, 6, 3, 9]],
3: [[12, 35, 42, 53, 70, 71, 74, 76, 6, 11, 16, 17, 38, 62, 66, 77]]
}

Answer 2

Try withitertools.chain.from_iterable:

>>> import itertools
>>> {k : [list(itertools.chain.from_iterable(v))] for k,v in dct.items()}
{1: [[1, 2, 3, 4, 5, 6, 7, 5, 1, 4, 34, 3, 65, 0, 2, 2, 5, 4, 5, 7, 8, 4, 7]],
2: [[1, 5, 4, 5, 0, 1, 4, 6, 2, 2, 3, 5, 6, 6, 3, 9]],
3: [[12, 35, 42, 53, 70, 71, 74, 76, 6, 11, 16, 17, 38, 62, 66, 77]]}

Answer 3

使用itertools.chain:

from itertools import chain
out = {k: [list(chain.from_iterable(l))]
for k,l in dic.items()}

输出:

{1: [[1, 2, 3, 4, 5, 6, 7, 5, 1, 4, 34, 3, 65, 0, 2, 2, 5, 4, 5, 7, 8, 4, 7]],
2: [[1, 5, 4, 5, 0, 1, 4, 6, 2, 2, 3, 5, 6, 6, 3, 9]],
3: [[12, 35, 42, 53, 70, 71, 74, 76, 6, 11, 16, 17, 38, 62, 66, 77]]}