嘿,我需要发送电子邮件通知每当一个事件发生,我能够发送电子邮件,但我不确定如何附加数据帧作为附件到它。
def send_mail(content):
# Defining Email Body and Notificaion type.
html_content='Hi Team,</br><strong>{}</br></br>Thanks</strong></br></br>'.format(content)
# Defining Email_Format.
message = Mail(
from_email='XXXXXX@.com',
to_emails=['XXXXXX@.com'],
subject='test',
html_content=html_content)
try:
sg = SendGridAPIClient(SENDGRID_API_KEY)
response = sg.send(message)
except Exception as e:
logging.error(e.message)
return None
我可以通过上面的代码发送通知,但我需要将数据框作为附件附加到该邮件,我不知道如何附加它。
df_to_attach。—我需要将此数据框作为附件附加
Id Name
1 rick
2 John
3 uran
4 Turan
Twilio SendGrid开发者布道者在此。
正如Joshua在评论中建议的那样,将您的数据框转换为CSV格式,然后作为CSV文件附加。像这样:
from sendgrid.helpers.mail import (Mail, Attachment, FileContent, FileName, FileType, Disposition, ContentId)
import base64
def send_mail(content, dataframe):
# Defining Email Body and Notificaion type.
html_content='Hi Team,</br><strong>{}</br></br>Thanks</strong></br></br>'.format(content)
# Defining Email_Format.
message = Mail(
from_email='XXXXXX@.com',
to_emails=['XXXXXX@.com'],
subject='test',
html_content=html_content)
base64_csv = base64.b64encode(dataframe.to_csv(index=False).encode())
message.attachment = Attachment(FileContent(base64_csv),
FileName('dataframe.csv'),
FileType('text/csv'),
Disposition('attachment'),
ContentId('datafrane'))
try:
sg = SendGridAPIClient(SENDGRID_API_KEY)
response = sg.send(message)
except Exception as e:
logging.error(e.message)
return None