关联数组，迭代键和值PHP LARAVEL

Question

我有这个数组：

array:43 [▼
"ALFA ROMEO" => array:1 [▼
0 => "145"
]
"AUDI" => array:6 [▼
0 => "A1"
1 => "A3"
2 => "A4"
3 => "A5"
4 => "AUDI 80"
5 => "Q3"
]
"BMW" => array:15 [▼
0 => "116I"
1 => "118I"
2 => "318I"
3 => "318IA"
4 => "320I"
5 => "320IA"
6 => "325I"
7 => "328I"
8 => "330I"
9 => "535I"
10 => "X1"
11 => "X3"
12 => "X5"
13 => "X6"
14 => "Z4"
]
]

我想这样做：

获取密钥(ALFA ROMEOAUDIBMW(并在表(品牌(中搜索该密钥，获取该品牌的id并在数组内迭代"ALFA ROEO"以获取模型(145(，并插入名为model_car(brand_id，model(的新表中。奥迪、宝马等也一样

我知道这很容易，但我的头脑不工作！

谢谢。

Answer 1

试试下面的代码，这可能会帮助你实现你想要的。

/* Let $array be the array posted by you. */
foreach ($array as $key => $data) {
/* Fetch brand id by name. Assuming the name field replace it by your own. */
$brand = Brands::where('name', $key)->first();
/* Prepare array of brand id and model to be mass inserted. */
$brandModel = [];
foreach ($data as $i => $model) {
$brandModel[$i]['brand_id'] = $brand->id;
$brandModel[$i]['model'] = $model;
}
ModelCar::insert($brandModel);        //Insert into the new table model_car
}