从数组中取出随机字符串，将其放入新数组中，然后再将其放回旧数组中

Question

我正试图制作一个从数组中随机选择两个项目的句子。第一个选择的项目会暂时从数组中删除，因此无法再次选择，然后第二个项目也会随机选择并添加到句子中。然后，为了重置它，以便以后可以再次执行此操作，我尝试将第一个选择的项添加回其初始数组中。

问题是，当我这样做时，chosenWord1会像我希望的那样在句子中显示为字符串，但chosenWord2会显示一个索引号。

array = ["word","another word", "yet another word"];
/* put a random word from the array in its own value and then 
remove it from the array so it can't be chosen in next step */
let chosenWord1 = array.splice(Math.random() * array.length, 1)[0];
/* pick another random word from the same, altered array */
let chosenWord2 = Math.floor(Math.random() * array.length);
/* a function that puts a sentence on the webpage concatenating the strings 
from chosenWord1 and chosenWord2 goes here. then... */
/* add back the previously removed word so this process can repeat again 
with the same items in the array as there was before anything was done to it */
array.splice(1,0,chosenWord1);

此外，如果有更明智的方式我可以构建这个，请告诉我。我还是个新手。

Answer 1

我不知道这是否是您所需要的，但这会重复提取两个随机单词，而不会将它们从原始数组中取出。for循环用于显示它如何处理不同的单词。

const array = ["word", "another word", "yet another word"];
const randomNumber = (key) => Math.floor(Math.random() * key);
for (let i = 0; i < 10; i++) {
const { [randomNumber(array.length)]: wordOne, ...rest } = array;
const { [randomNumber(array.length - 1)]: wordTwo } = Object.values(rest);
console.log(`${wordOne} and ${wordTwo}`);
}