尝试运行代码x次，如果失败x次，则引发异常

Question

有一个代码随机引发错误。

当代码失败时，我想重新运行它，但如果它失败了x次，我想引发一个自定义错误。

在Python中有合适的方法吗？

#我在想以下几点，但似乎不是最好的。

class MyException(Exception):
pass

try:
for i in range(x):
try:
some_code()
break
except:
pass
except:
raise MyException("Check smth")

Answer 1

只需创建一个在成功时中断的无限循环，并计算except块中的错误：

max_errors = 7
errors = 0
while True:
try:
run_code()
break
except ExceptionYouWantToCatch:  # You shouldn't use a bare except:
errors += 1
if errors > max_errors:
raise MyException

另一种方法：

max_errors = 7

for run in range(max_errors):
try:
run_code()
break
except ExceptionYouWantToCatch:  # You shouldn't use a bare except:
pass
else:  # will run if we didn't break out of the loop, so only failures
raise MyException

Answer 2

你可以这样做

for i in range(x):
retries = <how many times you want to try> 
while retries: # This could be while 1 since the loop will end in successful run or with exception when retries run out. 
try:
some code
break # End while loop when no errors
except:
retries =- 1
if not retries:
raise MyException("Check smth")